我有一个将数据提交到表格的表单。除了received_date
和gid
之外,其他用户可以修改表格列。如何在PHP的更新脚本中跳过列?
这是default_table(简化):
gid received_date detail max_number status
1 NULL NULL NULL 1
首次输入后:
gid received_date detail max_number status
1 2017-07-17 Swimsuit 100 1
在第二次输入后依次输入:
gid received_date detail max_number status
1 2017-07-17 Swimsuit XL 250 1
可能是这样的:
UPDATE t_goods
IF(t_goods.received_date = NULL){
SET received_dates = received_date(today_date), detail = detail, max_number = add_stock WHERE gid = gid
}
ELSE{
SET detail = detail, max_number = add_stock WHERE gid = gid
}
注意:查询只是一个伪代码。
答案 0 :(得分:2)
尝试那样。
UPDATE t_goods
SET
detail = detail,
max_number = add_stock,
received_date = IF(received_date IS NULL, received_dates,received_date)
WHERE gid = gid;
IF(received_date IS NULL, received_dates,received_date)
如果received_date为null,则此等式更新new received_dates值,否则将receive_date保留为旧值。
答案 1 :(得分:-1)
UPDATE t_goods SET received_dates = NOW(), detail = x, max_number = add_stock WHERE gid = gid AND t_goods.received_date IS NULL;
很难理解更多信息,这个怎么样?