php如何在mysql_fetch_array之后打印sql值

Question

我有SQL查询：

SELECT countryCode FROM itins_countries WHERE (itinID = 5);
$countriesIndex = mysql_fetch_array($countriesQuery);

现在，在我的代码的另一个艺术中，我想运行＆＃34; $ countriesIndex＆＃34;并打印它包含的所有值（＆＃34; countryCode＆＃34;）;

我该怎么做？

Answer 1

while($row = mysql_fetch_array($countriesQuery)){
     echo $row['column_name'];
     ///same for other columns
}

你可以使用while循环来循环直到所有数组元素都被打印

Answer 2

试试这个......

echo "<pre>";print_r($countriesIndex);

Answer 3

不推荐使用mysql_connect ...您可以使用mysqli_connect。

    $mysqli = mysqli_connect(DB_SERVER, DB_USER, DB_PASSWORD, DB_NAME);
    if (mysqli_connect_errno($mysqli)) {
        trigger_error('Database connection failed: '  . mysqli_connect_error(), E_USER_ERROR);
    }
    mysqli_set_charset($mysqli, "utf8");

    $sql = "SELECT countryCode FROM itins_countries WHERE (itinID = 5)";
    $result = mysqli_query($mysqli, $sql);
    $countries = [];
    while($row = $result->fetch_assoc())
    {
        $users_arr[] = $row;
    }
    $result->close();
    print_r($users_arr);