Question

我一直在讨论这个阵列：

Array (
    [invoicenr] => Array (  
                            [0] => 1234 
                            [1] => 1234 
                            [2] => 1234 
                            [3] => 4321 
                            [4] => 3214
                        ) 
    [invoicedate] => Array ( 
                            [0] => 17.07.2017. 
                            [1] => 17.07.2017. 
                            [2] => 17.07.2017. 
                            [3] => 11.07.2017. 
                            [4] => 11.07.2017. ) 
    [amount] => Array ( 
                            [0] => 10 
                            [1] => 1 
                            [2] => 23 
                            [3] => 10 
                            [4] => 1 ) 
    [cause] => Array ( 
                            [0] => 1 
                            [1] => 1 
                            [2] => 1 
                            [3] => 1 
                            [4] => 1 ) 
)

我试图根据第一级关键字＆＃34; invoicenr＆＃34;价值，但到目前为止没有运气。我期待结果：

Array (
       [invoicenr] => Array (  
                             [0] => 1234 
                             [1] => 1234 
                             [2] => 1234) 
       [invoicedate] => Array ( 
                             [0] => 17.07.2017. 
                             [1] => 17.07.2017. 
                             [2] => 17.07.2017.) 
       [amount] => Array ( 
                             [0] => 10 
                             [1] => 1 
                             [2] => 23) 
       [cause] => Array ( 
                             [0] => 1 
                             [1] => 1 
                             [2] => 1) 
            ) 
Array (
       [invoicenr] => Array (   
                             [0] => 4321 ) 
       [invoicedate] => Array ( 
                             [0] => 11.07.2017. ) 
       [amount] => Array ( 
                             [0] => 10) 
       [cause] => Array ( 
                             [0] => 1  ) 
        )
Array (
       [invoicenr] => Array (   
                             [0] => 3214 ) 
       [invoicedate] => Array (
                             [0] => 11.07.2017. ) 
       [amount] => Array ( 
                             [0] => 1) 
       [cause] => Array ( 
                             [0] => 1  ) 
        )

我想知道这是否可行以及如何，或者我需要先重写数组？

先谢谢大家，到目前为止，我是新编码和努力学习的人。：）

Answer 1

请发布您尝试解决问题的代码。

我相信你需要一个计数器（i）来通过invoicenr和一个记住最后一个值（Array [i]）的临时变量，并将它与invoicenr数组中的下一个值进行比较。如果值保持不变，如果它不同，则打印出所有其他数组[i]。

Answer 2

我已经完成了它，但我认为我的方式太原始了。这是我做的：

//Count number of rows in initial array
$rows = count(array_filter($_POST['invoicenr']));
//Crete unique array that contains only $_POST['invoicenr'] which i can count later
$uniquearray = array();
for ($row = 0; $row < $rows; $row++) { 
    $uniquearray[] = $_POST['invoicenr'][$row] ;
}
//return unique keys only
$invoicenrunique=array_keys(array_flip($uniquearray));
//count number of rows in unique array
$invoicenruniquecount=count(array_keys(array_flip($uniquearray)));
//do magic, this splits main array into n smaller arrays based on $_POST['invoicenr']
for($uniquerow = 0; $uniquerow < $invoicenruniquecount; $uniquerow++)   {
    $testarray = array();
    for ($row = 0; $row < $rows; $row++) { 
        if($_POST['invoicenr'][$row]==$invoicenrunique[$uniquerow]){
            $testarray[$row]['invoicenr']=$_POST['invoicenr'][$row];
            $testarray[$row]['invoicedate']=$_POST['invoicedate'][$row];
            $testarray[$row]['amount']=$_POST['amount'][$row];
            $testarray[$row]['cause']=$_POST['cause'][$row];
        } 
    }
    print_r(array_values($testarray));
    echo "<br>";
}

您对如何改进我的解决方案有任何建议吗？

祝你好运！

基于键值将二维数组拆分为n个

2 个答案: