我编写了代码来搜索字符串中的关键字并提取所需的数据,但是当我尝试使用名为sort,title和artist的数组中的关键字进行搜索时,我遇到了问题。当我这样做时,我得到一个关于潜在无限循环的错误。
var type = ['track','tracks','song','songs','album','albums'];
var artist = ['created by', 'made by'];
var genre = ['genre'];
var limit = ['set limit'];
var title = ['title','name'];
var sort = ['sort by', 'classificate by', 'separate by'];
var sortBy = ['popularity'];
// function changeWordsToNumbers(words) {
// if (msg.numbers[words])
// return msg.numbers[words];
// }
function searchForIndex(instruction, keywords) {
for (i = 0; i < keywords.length; i++) {
let search = instruction.search(keywords[i]);
if (search)
return search;
}
return false;
}
function getSearchResult(wanted) {
var searchResult = {
artist : searchForIndex(wanted, artist),
genre : searchForIndex(wanted, genre),
limit : searchForIndex(wanted, limit),
type : searchForIndex(wanted, type),
title : searchForIndex(wanted, title),
sort : searchForIndex(wanted, sort),
sortBy : searchForIndex(wanted, sortBy)
};
return searchResult;
}
function removeJunkKeyword(searchResult,instruction) {
for(var property in searchResult) {
if(searchResult.hasOwnProperty(property)) {
if(searchResult[property] != - 1) {
instruction = instruction.slice(0, searchResult[property] - 1);
}
}
}
return instruction;
}
function checkExist(searchResult) {
for(var property in searchResult) {
if(searchResult.hasOwnProperty(property)) {
if(searchResult[property] != -1)
return false;
}
}
return true;
}
function findAndCleanQuery(instruction, keywords) {
var exist = instruction.search(keywords);
var result = instruction.slice(exist + keywords.length + 1, instruction.length);
var searchResult = getSearchResult(result);
if (exist != -1) {
if (checkExist(searchResult)) {
return result;
} else {
result = removeJunkKeyword(searchResult,result);
return result;
}
}
return false;
}
function searchFor(instruction, keywords) {
for (i = 0; i < keywords.length; i++) {
let result = findAndCleanQuery(instruction,keywords[i]);
if (result)
return result;
}
return false;
}
function searchForType(instruction) {
for (i = 0; i < type.length; i++) {
let search = instruction.search(type[i])
if(search)
return type[i];
}
return false;
}
function searchForKeywords(instruction) {
msg.artist = searchFor(instruction, artist);
msg.type = searchForType(instruction, type);
msg.genre = searchFor(instruction, genre);
msg.limit = searchFor(instruction, limit);
msg.title = searchFor(instruction, title);
msg.sort = searchFor(instruction, sortreg);
}
var msg = {}
msg.instruction = 'Search for me';
searchForKeywords(msg.instruction);
console.log(msg.artist);
console.log(msg.type);
console.log(msg.genre);
console.log(msg.limit);
console.log(msg.title);
console.log(msg.sort);
PS。 node-red使用对象msg
在节点之间进行通信。
答案 0 :(得分:3)
问题在于你在几个循环中执行此操作:
for (i = 0; i < keywords.length; i++) {
......你应该这样做:
for (let i = 0; i < keywords.length; i++) {
不使用let
,变量i
实际上是全局的。每次进入一个新循环时它都会重置为0,因此它永远无法增加,从而创建了无限循环。
作为旁注,在第98行使用时,您还会注意到sortreg
未定义。