Question

最近我正在对我的Android应用程序进行debbuging，但是当我从我的Web服务接收数据时遇到了问题，因为在日志中，它说我发送的参数（List）是空的......事情就是这样。 ..当我用SOAP UI测试我的方法时，它工作！我得到了我想要的东西，但是从android开始，xml请求的构建方式与XML不同：

SOAP UI（此XML Works！）：

<soapenv:Envelope xmlns:soapenv="http://schemas.xmlsoap.org/soap/envelope/" 
xmlns:ws="http://ws.soap.net/">
   <soapenv:Header/>
<soapenv:Body>
  <ws:GetSomething>
     <!--Zero or more repetitions:-->
     <List>
        <!--Optional:-->
        <id>000001</id>
        <!--Optional:-->
        <type>Sign</type>
     </List>
  </ws:GetSomething>

如您所见，这是SOAP UI为我的ws

请求构建的xml

这是我在Android上调试时发现的XML：

<v:Envelope xmlns:i="http://www.w3.org/2001/XMLSchema-instance" 
xmlns:d="http://www.w3.org/2001/XMLSchema" 
xmlns:c="http://schemas.xmlsoap.org/soap/encoding/" 
xmlns:v="http://schemas.xmlsoap.org/soap/envelope/">
<v:Header />
<v:Body>
<n0:GetSomething xmlns:n0="http://ws.soap.net/">
<n0:List>
<id>000001</id>
<tipo>sign</tipo>
<id>000002</id>
<tipo>sign</tipo>
<id>000003</id>
<tipo>sign</tipo>
</n0:List>
</n0:GetSomething>
</v:Body>
</v:Envelope>

所以在Android上调试时生成的xml，当我粘贴在SOAP UI上时，只是说我发送的参数（一个List）是空的......

我测试了在Android中生成的XML，只有在我删除＆＃34; n0＆＃34;前缀＆＃34;列表＆＃34;我的意思是：

从这个：

到此：

<List>
</List>

这是我的Android SOAP请求：

  private final String SOAP_NAMESPACE = "http://ws.soap.net/";
private final StringURL_SOAP="http://MI_IP:PORT/GetSomeRest/WebServiceTest";
private final String SOAP_SOMETHING = "GetSomething";
private final String SOAP_ACTION_GETSOMETHING = "http://ws.soap.net/" + SOAP_SOMETHING;
    public SoapObject SendSigns(ArrayList<Signs> paramSigns)
{       
SoapObject request = new SoapObject(SOAP_NAMESPACE, SOAP_SOMETHING);

request.addSoapObject(buildArray(paramSigns));

SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(
        SoapEnvelope.VER11);

new MarshalBase64().register(envelope);
envelope.bodyOut = request;
envelope.setOutputSoapObject(request);
envelope.setAddAdornments(false);
envelope.implicitTypes= true;
envelope.dotNet=true;
envelope.headerOut = new org.kxml2.kdom.Element[1];

HttpTransportSE androidHttpTransport = new HttpTransportSE(URL_SOAP);

try {
    androidHttpTransport.debug = true;

    androidHttpTransport.call(SOAP_ACTION_GETSOMETHING, envelope);

    SoapObject Object = (SoapObject) envelope.getResponse();

    if(Object!=null)
    {
        return Object;
    }

} catch (Exception e) {
    Log.d("CALL DUMP", "requestError: "+androidHttpTransport.requestDump);
    Log.d("CALL DUMP", "responseEror: "+androidHttpTransport.responseDump);
    Log.e("ERROR: ", String.valueOf(e));

}        
return null;

}

Answer 1

你是否在URL_SOAP和String之间加了空格？

这是你的代码：

private final StringURL_SOAP="http://MI_IP:PORT/GetSomeRest/WebServiceTest";

正确：

private final String URL_SOAP="http://MI_IP:PORT/GetSomeRest/WebServiceTest";

如何从SOAP构建SOAP请求，如SOAP UI请求？

1 个答案: