Question

我有一个字符串

package main

import "fmt"

func sum(a []int, c chan int) {
    sum := 0
    for _, v := range a {
        sum += v
    }
    c <- sum // send sum to c
}

func main() {
    a := []int{7, 2, 8, -9, 4, 0}

    c := make(chan int)
    go sum(a[:len(a)/2], c)
    go sum(a[len(a)/2:], c)
    x, y := <-c, <-c // receive from c

    fmt.Println(x, y, x+y)
}

和一个清单

   item1="Act the way that the people around you are acting."

表示if条件，

   list1=['Act the way that the people around you are acting.', "This phrase might come in handy when you're traveling abroad notice that people do things differently than you're used to."]

它总是失败，但字符串存在于列表中。请帮忙

   if item1 in list1:
       print(item1)

在list1中看到此item1未获得True，请帮助

Answer 1

我尝试了以下代码（编辑以查看长行），

item1="Act the way that the people around you are acting."
list1=['Act the way that the people around you are acting.',
  "This phrase might come in handy when you're traveling abroad " +
  "notice that people do things differently than you're used to."]
if item1 in list1:
  print(item1)

并打印

按照你周围的人的行事方式行事。

因此，问题出在其他地方。

代码的第一部分df1,不是有效的Python代码（可能是问题出在哪里）。编辑您的帖子，以便它是一个最小，完整且可验证的示例（https://stackoverflow.com/help/mcve）。

Answer 2

我认为item1肯定不在list1中，否则会进入if声明。我会打印出item1和list1的值来查看错误。如果你能给我两个数据帧的确切值，我可以帮助你。代码编写得非常糟糕

当字符串已存在于python的列表中时获取False

2 个答案: