给出了以下JSON-File:
{
"name": "yiisoft/yii2-app-advanced",
"description": "Yii 2 Advanced Project Template",
"keywords": ["yii2", "framework", "advanced", "project template"],
"homepage": "http://www.yiiframework.com/",
"type": "project",
"license": "BSD-3-Clause",
"support": {
"issues": "https://github.com/yiisoft/yii2/issues?state=open",
"forum": "http://www.yiiframework.com/forum/",
"wiki": "http://www.yiiframework.com/wiki/",
"irc": "irc://irc.freenode.net/yii",
"source": "https://github.com/yiisoft/yii2"
},
"minimum-stability": "dev",
"require": {
"php": ">=5.4.0",
"yiisoft/yii2": "~2.0.6",
"yiisoft/yii2-bootstrap": "~2.0.0",
"yiisoft/yii2-swiftmailer": "~2.0.0"
},
"require-dev": {
"yiisoft/yii2-debug": "~2.0.0",
"yiisoft/yii2-gii": "~2.0.0",
"yiisoft/yii2-faker": "~2.0.0",
"codeception/base": "^2.2.3",
"codeception/verify": "~0.3.1"
},
"config": {
"process-timeout": 1800
},
"repositories": [
{
"type": "composer",
"url": "https://asset-packagist.org"
}
]
}
如何读出属性最小稳定性? 以下代码因丢失错误而失败:qnips_JSON_Loesung.html:112 Uncaught ReferenceError:未定义稳定性
output+="<th class='spalte'>"+daten.minimum-stabilty+"</th></tr>";
顺便说一句,以下构造工作非常好:
output+="<th class='spalte'>"+daten.keywords+"</th></tr>";
答案 0 :(得分:1)
- 让JavaScript认为它是一个计算。
在创建文件时删除它,或者像地图一样访问它。
答案 1 :(得分:1)
此处 daten.minimum-stabilty 与此表达式混淆(即 daten.minimum - stablety )。它认为在 daten.minimum 和稳定性之间减去
要访问包含不允许显示为标识符的破折号或其他字符的密钥,请使用括号表示法
daten["minimum-stabilty"];
您是否尝试过这样访问包含-
的json密钥?
var json_with_dash_key = daten["minimum-stabilty"];
output+="<th class='spalte'>"+ json_with_dash_key +"</th></tr>";
答案 2 :(得分:0)
使用 daten [&#34; minimum-stabilty&#34;] 应该可以正常使用
与此问题相关的旧帖子中也提出了其他替代方法:Unable to access JSON property with "-" dash
答案 3 :(得分:0)
以下代码解决了我的问题:
for(let j in daten["require-dev"]){
output+="<label> Version "+daten["require-dev"][j]+"<br></label>";
}