我正在尝试学习jquery,我想创建循环通过图像的fadein和fadeout效果。我使用了setInterval函数来循环遍历图像,但它只适用于第一次迭代。
$(document).ready(function() {
var newcount = 0;
var image = $(".image-store img");
image.hide();
var image_array = [];
image.each(function() {
image_array.push($(this).attr('src'));
});
var showimg = $(".image-disp img");
showimg.attr("src", image_array[newcount]);
setInterval(function() {
showimg.fadeOut(2000, function() {
newcount = newcount + 1;
showimg.attr("src", image_array[newcount]);
showimg.fadeIn(2000);
});
if (newcount == image_array.length) {
newcount = -1;
}
}, 3000);
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div class="image-store">
<img src="img/img1.jpg">
<img src="img/img2.jpg">
<img src="img/img3.jpg">
</div>
<div class="image-disp">
<img src="">
</div>
答案 0 :(得分:2)
它有效,但您在代码末尾缺少});
。使用浏览器控制台知道是否有任何错误。
答案 1 :(得分:1)
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17
&#13;
$(document).ready(function() {
var newcount = 0;
var image = $(".image-store img");
image.hide();
var image_array = [];
image.each(function() {
image_array.push($(this).attr('src'));
});
var showimg = $(".image-disp img");
showimg.attr("src", image_array[newcount]);
setInterval(function() {
showimg.fadeOut(2000, function() {
newcount = newcount + 1;
showimg.attr("src", image_array[newcount]);
showimg.fadeIn(2000);
});
if (newcount == image_array.length) {
newcount = -1;
}
}, 3000);
});
&#13;