Question

我在pageA中有两个链接。当我点击第一个链接时，它会重定向到另一个名为pageB的页面并执行某些特定的工作并返回到pageA。从这里它应该再次点击到第二个链接，但它表示页面已重新加载，没有可用的缓存。

//List of all tickets
for(WebElement ticket: ticketList){
List<WebElement> ticketCells = ticket.findElements(By.tagName('td'));
  if(ticketCells.get(4).getText().equalIgnoreCase("Some Text")){
   ticketCells.get(2).click(); //Redirects to pageB
   .....
   do some job
   .......
   //Finally clicking on the 'SAVE & BACK' button which should return  to previous 
   //page and pick the 2nd ticket from the list of all tickets (1st for loop) 
   driver.findElement(By.id("save&back")).click();
  }
}

虽然它会回到上一页pageA，但无法从for循环中选择第二个元素进行下一步操作。

关于如何使其发挥作用的任何想法。

Answer 1

我认为您想要的就是按浏览器的后退按钮，对吧？

如果是这样，请尝试以下操作：

webDriver.navigate().back();

Answer 2

@try-catch-finally explained it very clearly. The below code is exactly what you need to handle the error.

for(int i = 0; i <2 ;i++){
ticketList = driver.findElements(selector);
ticket = ticketList.get(i);
List<WebElement> ticketCells = ticket.findElements(By.tagName('td'));
  if(ticketCells.get(4).getText().equalIgnoreCase("Some Text")){
   ticketCells.get(2).click(); //Redirects to pageB
   .....
   do some job
   .......
   //Finally clicking on the 'SAVE & BACK' button which should return  to previous 
   //page and pick the 2nd ticket from the list of all tickets (1st for loop) 
   driver.findElement(By.id("save&back")).click();
  }
}

Selenium Java如何将驱动程序返回上一页

2 个答案: