我已经读过字符串并从中构建一个html表:
var ShoesXML = "<All><Shoe><Name>All Stars</Name><BrandName>Converse</BrandName><ReleaseDate>10/2/08</ReleaseDate><Picture>pic.jpg</Picture></Shoe><Shoe><Name>All Star1s</Name><BrandName>Converse1</BrandName><ReleaseDate>11/2/08</ReleaseDate><Picture>pic.jpg</Picture></Shoe></All>";
$(document).ready(function() {
xmlDoc=$.parseXML( ShoesXML );
$(xmlDoc).find("Shoe").each(function(i, n) {
var html = "<tr>\n" +
"<td><span>" + $(n).find("Name").text() + "</span></td>\n" +
"<td>" + $(n).find("BrandName").text() + "</td>\n" +
"<td>" + $(n).find("ReleaseDate").text() + "</td>\n" +
"<td><img src='" + $(n).find("Picture").text() + "'></td>\n" +
"</tr>";
$("table.shoetable tbody").append(html);
});
});
我尝试以这种方式设置值,但没有成功:
$(n).find("Name").text("NEW VALUE")
答案 0 :(得分:1)
在构建.textContext
字符串
HTML
$(n).find("Name").text("NEW VALUE")
var html = "<tr>\n" +
"<td><span>" + $(n).find("Name").text() + "</span></td>\n" +
"<td>" + $(n).find("BrandName").text() + "</td>\n" +
"<td>" + $(n).find("ReleaseDate").text() + "</td>\n" +
"<td><img src='" + $(n).find("Picture").text() + "'></td>\n" +
"</tr>";