将函数值返回为float Python 3.6.1

时间:2017-07-16 03:25:12

标签: python function math hypotenuse

我收到以下错误,似乎无法弄清楚如何修复。遵循逻辑,我调用3个函数,所有3个返回值为float,然后我对存储的返回值执行一些数学运算并将其打印为float。那么哪里出错了?我在A面输入4,在B面输入5。

错误消息:

输入A面的长度:4.0 输入B面的长度:5.0

Traceback (most recent call last):
  File "python", line 26, in <module>
  File "python", line 9, in main
  File "python", line 24, in calculateHypotenuse
TypeError: unsupported operand type(s) for ^: 'float' and 'float'
import math

def main():
  #Call get length functions to get lengths.
  lengthAce = getLengthA()
  lengthBee = getLengthB()

  #Calculate the length of the hypotenuse
  lengthHypotenuse = calculateHypotenuse(float(lengthAce),float(lengthBee))

  #Display length of C (hypotenuse)
  print()
  print("The length of side C 'the hypotenuse' is {}".format(lengthHypotenuse))

#The getLengthA function prompts for and returns length of side A  
def getLengthA():
  return float(input("Enter the length of side A: "))

#The getLengthA function prompts for and returns length of side B
def getLengthB():
  return float(input("Enter the length of side B: "))

def calculateHypotenuse(a,b):
  return math.sqrt(a^2 + b^2)

main()

print()
print('End of program!')

1 个答案:

答案 0 :(得分:1)

Python中的

^bitwise XOR operator,而不是幂运算符:

  

^运算符产生其参数的按位XOR(异或),它必须是整数

您需要使用**,而 是权力运营商:

def calculateHypotenuse(a,b):
  return math.sqrt(a**2 + b**2)