Question

此程序不会创建两个以上的空文件。

#include<stdio.h>
#include<string.h>
#include<stdlib.h>

int create(char filename[])
{
    char filext[10+1]=".";
    printf("\nEnter File Extension :");
    scanf("%9s",filext+1);
        FILE* fp;
        strcat(filename, filext);
        fp = fopen(filename,"w");
        if(!fp)
        {
            return 0;
        }
        fclose(fp);
        return 1;

}
int main(int argc , char* argv[])
{
    int f;
    int i;
    char* j;
    char buffer[33];
    char filename[100];
    if (argc == 3)
    {
        for(i = 0; i < atoi(argv[2]) ; i++)
        {
            j = itoa(i,buffer,10);
            strcpy(filename,strcat(argv[1],j));
            f = create(filename);
            if(f==0)
            {
                printf("error in creating files . check uac!!!");
            }
            else{
                printf("\nfile Created ...\n");
            }   
        }
    }
    else{
        printf("syntax Error");
    }
    return 0;
}

当我尝试执行该文件时，我得到以下输出。

F:\selfcreatedtools\filegen>gcc gen.c

F:\selfcreatedtools\filegen>a wander 4

Enter File Extension :php

file Created ...

Enter File Extension :mag

file Created ...

F:\selfcreatedtools\filegen>

当我在命令行中传递argv[2] = 4时。根据程序循环必须迭代4次。并提供4个文件作为输出。但我的程序会生成2个文件，然后循环停止迭代。

感谢您的解决方案。我是初学者。

Answer 1

这是一个没有提示扩展的解决方案 - 您可以在命令行上提供它。它使用我的错误报告功能，stderr.c和stderr.h #include "stderr.h" #include <stdio.h> #include <stdlib.h> #include <string.h> static int create(const char *base, int numlen, int number, const char *dot, const char *extn) { int rc = 0; char filename[1024]; snprintf(filename, sizeof(filename), "%s%.*d%s%s", base, numlen, number, dot, extn); FILE *fp = fopen(filename, "w"); if (fp == 0) { err_sysrem("failed to create file '%s': ", filename); rc = -1; } else fclose(fp); return rc; } int main(int argc, char **argv) { err_setarg0(argv[0]); if (argc < 3 || argc > 4) err_usage("base number [ext]"); char *base = argv[1]; int number = atoi(argv[2]); const char *dot = "."; char *extn = argv[3]; if (extn == 0) { dot = ""; extn = ""; } if (*extn == '.') dot = ""; char buffer[32]; int numlen = snprintf(buffer, sizeof(buffer), "%d", number - 1); int rc = EXIT_SUCCESS; for (int i = 0; i < number; i++) { if (create(base, numlen, i, dot, extn) != 0) rc = EXIT_FAILURE; } return rc; }提供。

gen29

它使用https://github.com/jleffler/soq/tree/master/src/libsoq来管理字符串连接。

示例运行（程序名为$ gen29 base 10 created: [base0] created: [base1] created: [base2] created: [base3] created: [base4] created: [base5] created: [base6] created: [base7] created: [base8] created: [base9] $ gen29 base 10 .ext created: [base0.ext] created: [base1.ext] created: [base2.ext] created: [base3.ext] created: [base4.ext] created: [base5.ext] created: [base6.ext] created: [base7.ext] created: [base8.ext] created: [base9.ext] $ gen29 base 13 xtn created: [base00.xtn] created: [base01.xtn] created: [base02.xtn] created: [base03.xtn] created: [base04.xtn] created: [base05.xtn] created: [base06.xtn] created: [base07.xtn] created: [base08.xtn] created: [base09.xtn] created: [base10.xtn] created: [base11.xtn] created: [base12.xtn] $）：

如果你真的想在文件创建中做提示，请成为我的访客并进行修改，但是IMO这样的程序没有那些没有提示的程序。

c文件处理程序无法创建2个以上的文件

1 个答案: