我有一个异步瀑布数组,其中函数otherIngrLists()是要执行的第三个。之前的每个功能都运行良好。
function otherIngrLists(userslist, callback){
collection = db.get('ingrList');
collection.find({"userid":{$ne:userid}},{},function(err,docs){
if(!err){
var otherLists = docs;
var otherListsCount = docs.count();
console.log(otherListsCount);
callback(null, otherLists, otherListsCount, userslist);
} else {
callback(err, null);
}
});
},
问题是这个函数被调用了两次。我用一个简单的console.log()确认了这一点。
我是如何设法再次调用此功能的?当我使用它们传递给下一个函数时,我是否错误地回调了回调的概念?
此函数执行两次后,也会抛出错误。它对这个问题没有任何意义,我稍后会关注自己。 谢谢你的时间!
router.get中的瀑布数组:
router.get('/:userid', function(req, res) {
var db = req.db;
var collection;
var userid = req.params.userid;
async.waterfall(
[
function getIngrList(callback, userid) {
var route = 'http://localhost:3000/users/zutatenliste/'+userid;
request(route, function(err, response, body){
if (!err && response.statusCode === 200) {
var userlist = body;
callback(null, userlist);
} else {
callback(err, null);
return;
}
});
},
function otherIngrLists(userlist, callback){
collection = db.get('zutatenListe');
console.log(userid);
collection.find({"userid":{$ne:userid}},{},function(err,docs){
if(!err){
var otherLists = docs;
var otherListsCount = docs.count();
callback(null, otherLists, otherListsCount, userlist);
} else {
callback(err, null);
}
});
},
function pushInArray(otherLists, otherListsCount, userlist, callback){
console.log("test");
...
...}
}
}
编辑1: - 如果案件被执行,首先是真实的,然后是假的 - //不再发生了
编辑2:添加整个事物直到有问题的功能
答案 0 :(得分:0)
请提供一些额外的详细信息,因为此功能看起来很完美,不,您没有误解您正确使用它的回调概念。
异步瀑布的结构
var create = function (req, res) {
async.waterfall([
_function1(req),
_function2,
_function3
], function (error, success) {
if (error) { alert('Something is wrong!'); }
return alert('Done!');
});
};
function _function1 (req) {
return function (callback) {
var something = req.body;
callback (null, something);
}
}
function _function2 (something, callback) {
return function (callback) {
var somethingelse = function () { // do something here };
callback (err, somethingelse);
}
}
function _function3 (something, callback) {
return function (callback) {
var somethingmore = function () { // do something here };
callback (err, somethingmore);
}
}
so, in waterfall you can pass the values to the next function and your 3rd function is correct.
被修改
async.waterfall(
[
//can not give userId as second parameter
function getIngrList(callback) {
//if you want userId you can pass as I shown above or directly use here if it's accessible
var route = 'http://localhost:3000/users/zutatenliste/'+userid;
request(route, function(err, response, body){
if (!err && response.statusCode === 200) {
var userlist = body;
callback(null, userlist);
} else {
callback(err, null);
// return; no need
}
});
},
function otherIngrLists(userlist, callback){
collection = db.get('zutatenListe');
console.log(userid);
collection.find({"userid":{$ne:userid}},{},function(err,docs){
if(!err){
var otherLists = docs;
var otherListsCount = docs.count();
callback(null, otherLists, otherListsCount, userlist);
} else {
callback(err, null);
}
});
},
function pushInArray(otherLists, otherListsCount, userlist, callback){
console.log("test");
...
...}
如上所述,你无法在那里传递userId作为最后一个参数。如果您仍然遇到同样的错误,请告诉我。
答案 1 :(得分:0)
首先你需要声明你的功能:
function myFuntion(userId, callback) {
async.waterfall([
function(callback) {
//do some thing here
callback(null, userlist);
}, function(userId, callback) {
//do something here
callback(null, orderList, orderListCount, userlist);
}
], function(err, orderList, orderListCount, userlist) {
if(err)
console.log(err);
else
callback(orderList, orderList, userlist);
})
}
之后你可以使用功能:
myFuntion(userId, function(orderList, orderListCount, userlist) {
console.log(orderList);
console.log(orderListCount);
console.log(userlist);
})