Question

我用烧瓶创建了一个简单的Web应用程序。现在在模型中，我有一个条形表，它与另外两个表有关系。

    user_shipper_id = Column(Integer, ForeignKey('user_shipper.id', ondelete='CASCADE'), nullable=False)
user_receiver_id = Column(Integer, ForeignKey('user_receiver.id', ondelete='CASCADE'), nullable=False)

现在user_shipper，我有这个：

        bars = relationship('bar',backref='shipper',lazy='dynamic')

也在user_receiver表中：

bars = relationship('bar',backref='receiver',lazy='dynamic')

现在我有一个问题：在吧台init功能我有这个：

    def __init__(self, origin, destination, tonage, load_date, unload_date, load_address, unload_adress, unload_type, packing, act_type, truck_type, payment_type):
    self.origin = origin
    self.destination = destination
    self.tonage = tonage
    self.load_date = load_date
    self.unload_date = unload_date
    self.load_adress = load_adress
    self.unload_type = unload_type
    self.unload_adress = unload_adress
    self.packing = packing
    self.act_type = act_type
    self.truck_type = truck_type
    self.payment_type = payment_type

现在当我尝试使用sqlalchemy插入表格时显示错误并说出：

TypeError: __init__() got an unexpected keyword argument 'receiver'

当我尝试插入时如何传递ForeignKey？我应该在init函数中定义一些东西吗？

Answer 1

您需要在对象初始化时传递user_receiver_id和user_shipper_id。

我没有对此进行过测试，但您可以尝试将其用作洞察力！

class UserShipper():
    ...
    bars = relationship('Bar', back_populates='shipper', lazy='dynamic')


class UserReceiver():
    ...
    bars = relationship('Bar', back_populates='receiver', lazy='dynamic')


class Bar():
    ...
    user_shipper_id = Column(Integer, ForeignKey('user_shipper.id', ondelete='CASCADE'), nullable=False)
    shipper = relationship('UserShipper', back_populates='bars')

    user_receiver_id = Column(Integer, ForeignKey('user_receiver.id', ondelete='CASCADE'), nullable=False)
    receiver = relationship('UserReceiver', back_populates='bars')

    def __init(self, ..., user_shipper_id, user_receiver_id):
        ...
        self.user_shipper_id = user_shipper_id
        self.user_receiver_id = user_receiver_id

如何在sqlalchemy中传递ForeignKey

1 个答案: