如何从用户获取字符串并将其存储在大小为10的字符数组中

Question

以下是我的代码。我正在尝试编写一个从用户获取字符串并将其存储在大小为10的字符数组中的程序。我想从左侧显示一个计数字母的子字符串，其中count由用户给出并打印如果用户按计数输入超出范围的字符串，则为适当的消息。

但我的代码抛出CRT内存分配错误，现在是“LNK1168”。enter image description here

我该如何解决这个问题？

#include<iostream>
#include<string>

using namespace std;

       void Destructor(char *p)// function 
       {
       int i = 0;

       cout << "Showing the substring .. " << p << endl << endl;;



      }

      char* left(const char* target, const int count)
     {
       char* ptr = NULL;// initialization of pointer 

       ptr = new char[count];// allocating dynaic memory ..

       cout << ptr << endl << endl;

       if (count > 10)
      {
        cout << " Input is out of range " << endl;
      }

     else
      {
           for (int i = 0; i < count; i++)
          {
            ptr[i] = target[i];
            cout << ptr[i] << endl;
            if (i == count - 1)
            {
                ptr[i + 1] = '\0';
                break;
                }
         }
          cout << ptr << endl;

          Destructor(ptr);//function call ....
      }


    return ptr;
}

void main()
{
    const int SIZE = 10;
    int count = 0;
    char* ptr = NULL;
    string userInput;
    char arr[SIZE] = { '\0' };

    ptr = arr;

    cout << "Please Enter a string :-";
    getline(cin, userInput);

    for (int i = 0; i <SIZE; i++)
    {
        ptr[i] = userInput[i];
        cout << "COUNT " << i << endl;
        if (i == SIZE - 1)
        {
            ptr[i + 1] = '\0';
            break;
        }
        if (userInput[i] == '\0')
            break;
    /*if (i == 9)
        break;*/
    }


    cout << "Checking character array in main .. " << ptr << endl;

     cout << "Enter a substring count : ";
     cin >> count;

     ptr = left(ptr, count);// function call...


     delete ptr;//deleting new memory ...
 }