Question

试图“反向工程”其他SO用户问题/答案我的问题但不能。 JOINS仍然没有找到我。

我有三个表：种族（所有种族的列表），结果（每个种族的结果），驱动程序（驱动程序信息）。并非所有车手都参加了特定赛道的所有比赛。

比赛表

| race_id   | track_id   | year   | complete |
+-----------+------------+--------+----------+
| 1         | 1          | 2006   | 1        |
| ...       | ...        | ...    | ...      |
| 21        | 1          | 2007   | 1        |
| ...       | ...        | ...    | ...      |
| 135       | 1          | 2008   | 1        |
| ...       | ...        | ...    | ...      |
| 215       | 1          | 2009   | 1        |
| ...       | ...        | ...    | ...      |
| 292       | 1          | 2010   | 1        |
| ...       | ...        | ...    |...       |
| 351       | 1          | 2011   | 0        |
+-----------+------------+--------+----------+

结果表

| race_id | driver_id | finish |
+---------+-----------+--------+
| 135     | 1         | 15     |
| ...     | ...       | ...    |
| 292     | 1         | 6      |
+---------+-----------+--------+

驱动程序表

| driver_id | name       |
+-----------+------------+
| 1         | Joe Driver |
+-----------+------------+

我想要一个显示的结果集：

| name       | race_id |  year  | finish |
+------------+---------+--------+--------+
| Joe Driver | 21      | 2007   | NULL   |
| Joe Driver | 135     | 2008   | 15     |
| Joe Driver | 215     | 2009   | NULL   |
| Joe Driver | 292     | 2010   | 6      |
+------------+---------+--------+--------+

Joe Driver仅参加了2006年之后在track_id = 1的4场比赛中的2场比赛，仅包括完成的比赛（1）

这是我目前的查询：

SELECT driver.driver, race.id, race.year, result.finish
FROM race
LEFT JOIN result ON race.id = result.race_id
LEFT JOIN driver ON result.driver_id = driver.driver_id
WHERE race.track_id = 1
AND race.year > 2006
AND race.complete = 1
AND driver.driver_id = 1
ORDER BY race.id ASC

我得到的结果只显示了司机所在的比赛：

| name       | race_id |  year  | finish |
+------------+---------+--------+--------+
| Joe Driver | 135     | 2008   | 15     |
| Joe Driver | 292     | 2010   | 6      |
+------------+---------+--------+--------+

我确定我忽略了加入JOINS的简单规则？

谢谢！

Answer 1

SELECT  driver.driver, race.id, race.year, result.finish
FROM    race
CROSS JOIN
        driver
LEFT JOIN
        result
ON      result.race_id = race.id
        AND result.driver_id = driver.driver_id
WHERE   race.track_id = 1
        AND race.year > 2006
        AND race.complete = 1
        AND driver.driver_id = 1
ORDER BY
        race.id ASC

MYSQL LEFT JOIN 3表包含NULL集

1 个答案: