简单的java代码出错

时间:2017-07-15 04:00:15

标签: java

我正在研究线性回归,我想要实现它。我想在“data.txt”文本文件中获取有关线性回归数据的信息。我使用Scanner类来读取文件。我也想把它们放在类变量中。当我使用'for loop'将它们变为可变时,我遇到了Error。

这是错误信息

Exception in thread "main" java.lang.ArrayIndexOutOfBoundsException: 0
    at linearregression.LinearRegression.initFile(LinearRegression.java:35)
35 line is `y[i]=scan.nextInt();`

,代码是

    private final double LEARNING_RATE=0.0001;

    private int num_TrainingSet;
    private int num_Features;

    private int[][] x;
    private int[] y;
    private double[] theta;

    private Scanner scan;

    public LinearRegression()
    {
        x = new int[num_TrainingSet][num_Features];
        y = new int[num_TrainingSet];
        theta = new double[num_Features+1];
    }

    public void initFile() throws FileNotFoundException
    {
        File file = new File("src/linearregression/data.txt");
        scan = new Scanner(file);
        num_TrainingSet = scan.nextInt();
        num_Features = scan.nextInt();
        for(int i=0;i<num_TrainingSet;i++)
        {
            y[i]=scan.nextInt();
        }
    }

当我也将此代码y[i]=scan.nextInt()更改为y[i]=0时; ,也遇到错误。

1 个答案:

答案 0 :(得分:0)

您的构造函数为x和y数组分配内存:

    x = new int[num_TrainingSet][num_Features];
    y = new int[num_TrainingSet];

但此时,num_TrainingSetnum_Features均为0,因为您尚未实际初始化这些变量。因此,在构造函数中分配的数组都是零长度。

相反,在用户输入后,在initFile方法中分配数组。

    num_TrainingSet = scan.nextInt();
    num_Features = scan.nextInt();
    x = new int[num_TrainingSet][num_Features];
    y = new int[num_TrainingSet];