我希望有人可以指出我在哪里出错了,但是我在过去的30分钟里一直在看这个,而且没有随处可见。
我有一个填充了数据的临时表,前端应用程序无法为我做任何逻辑,所以请原谅表中丑陋的case语句逻辑。
当我获得前10名记录时,用户对结果集感到满意。他们现在已经决定要将剩下的一组国家(不排在前10名的所有国家)视为“其他”。
我曾尝试创建一组不在前10名但却没有工作的国家,我正在计划将这一结果提升到前10名。
SELECT c.Country, count(*) AS 'Total_Number_of_customers', COALESCE(ili.new_customers,0) AS 'New_Customers', COALESCE(ilb.existing_first,0) AS 'Existing_First_Trans', COALESCE(ilc.existing_old,0) AS 'Existing_Prev_Trans'
FROM #customer_tmp c
LEFT JOIN (SELECT z.country, count(*) AS 'new_customers' FROM #customer_tmp z where z.customer_type='New_Customer' group by z.country)ili ON ili.country = c.country
LEFT JOIN (SELECT zy.country, count(*) AS 'existing_first' FROM #customer_tmp zy where zy.customer_type='Existing_Customer' AND zy.first_transaction=1 group by zy.country)ilb ON ilb.country = c.country
LEFT JOIN (SELECT zx.country, count(*) AS 'existing_old' FROM #customer_tmp zx where zx.customer_type='Existing_Customer' AND zx.first_transaction=0 group by zx.country)ilc ON ilc.country = c.country
GROUP BY c.country, ili.new_customers, ilb.existing_first, ilc.existing_old
ORDER BY 2 DESC
这是我用来从我的表中获取结果的SQL。
作为参考,我临时表中的每一行都包含一个客户ID,它们的创建日期和客户类型,这些都是我想要实现的目标。
希望这是一个简单的问题,我只是有点慢......
非常感谢Adv。
答案 0 :(得分:3)
使用EXCEPT
operator in SQL Server:
SELECT <fields>
FROM <table>
WHERE <conditons>
EXCEPT
<Query you want excluded>
答案 1 :(得分:2)
烨;除了,或者可能在查询中添加行号,然后选择:
SELECT * FROM (
SELECT c.Country, count(*) AS 'Total_Number_of_customers',
row_number() OVER (ORDER BY COUNT(*) DESC) AS 'r',
COALESCE(ili.new_customers,0) AS 'New_Customers', COALESCE(ilb.existing_first,0) AS 'Existing_First_Trans', COALESCE(ilc.existing_old,0) AS 'Existing_Prev_Trans'
FROM #customer_tmp c
LEFT JOIN (SELECT z.country, count(*) AS 'new_customers' FROM #customer_tmp z where z.customer_type='New_Customer' group by z.country)ili ON ili.country = c.country
LEFT JOIN (SELECT zy.country, count(*) AS 'existing_first' FROM #customer_tmp zy where zy.customer_type='Existing_Customer' AND zy.first_transaction=1 group by zy.country)ilb ON ilb.country = c.country
LEFT JOIN (SELECT zx.country, count(*) AS 'existing_old' FROM #customer_tmp zx where zx.customer_type='Existing_Customer' AND zx.first_transaction=0 group by zx.country)ilc ON ilc.country = c.country
GROUP BY c.country, ili.new_customers, ilb.existing_first, ilc.existing_old
ORDER BY 2 DESC
) sub_query WHERE sub_query.r >= 10
这可能更灵活,因为您可以运行一个查询,然后将结果分成“十大”和“其余”非常容易。
(这相当于鲍勃的答案;我想我们正在同时处理这个问题!)
答案 2 :(得分:2)
这是一种使用公用表表达式(CTE)的方法
WITH CTE AS
(
SELECT c.Country, count(*) AS 'Total_Number_of_customers', COALESCE(ili.new_customers,0) AS 'New_Customers', COALESCE(ilb.existing_first,0) AS 'Existing_First_Trans', COALESCE(ilc.existing_old,0) AS 'Existing_Prev_Trans'
, ROW_NUMBER() OVER (ORDER BY count(*) DESC) AS sequence
FROM #customer_tmp c
LEFT JOIN (SELECT z.country, count(*) AS 'new_customers' FROM #customer_tmp z where z.customer_type='New_Customer' group by z.country)ili ON ili.country = c.country
LEFT JOIN (SELECT zy.country, count(*) AS 'existing_first' FROM #customer_tmp zy where zy.customer_type='Existing_Customer' AND zy.first_transaction=1 group by zy.country)ilb ON ilb.country = c.country
LEFT JOIN (SELECT zx.country, count(*) AS 'existing_old' FROM #customer_tmp zx where zx.customer_type='Existing_Customer' AND zx.first_transaction=0 group by zx.country)ilc ON ilc.country = c.country
GROUP BY c.country, ili.new_customers, ilb.existing_first, ilc.existing_old
)
SELECT *
FROM CTE
WHERE sequence > 10
ORDER BY sequence
答案 3 :(得分:1)
SELECT country, COUNT(*) cnt, SUM(new_customer), SUM(existing_first_trans), SUM(existing_prev_trans)
FROM (
SELECT CASE
WHEN country IN
(
SELECT TOP 10 country
FROM #customer_tmp
ORDER BY
COUNT(*) DESC
) THEN
country
ELSE 'Others'
END AS country,
CASE WHEN customer_type = 'New_Customer' THEN 1 END AS new_customer,
CASE WHEN customer_type = 'Existing_Customer' AND first_transaction = 1 THEN 1 AS existing_first_trans,
CASE WHEN customer_type = 'Existing_Customer' AND first_transaction = 0 THEN 1 AS existing_prev_trans,
FROM #customer_tmp
)
GROUP BY
country
ORDER BY
CASE country WHEN 'Others' THEN 2 ELSE 1 END, cnt DESC