Question

在以下代码的第二行：studySpell(Confundo() 函数studySpell通过将Confundo类分配给spell来创建spell.incantation类的新实例。我的问题是，在执行倒数第二行之后，为什么'Accio'会返回'Confundo'？它不应该返回class Spell(object): def __init__(self, incantation, name): self.name = name self.incantation = incantation def __str__(self): return self.name + ' ' + self.incantation + '\n' + self.getDescription() def getDescription(self): return 'No description' def execute(self): print(self.incantation) class Accio(Spell): def __init__(self): Spell.__init__(self, 'Accio', 'Summoning Charm') class Confundo(Spell): def __init__(self): Spell.__init__(self, 'Confundo', 'Confundus Charm') def getDescription(self): return 'Causes the victim to become confused and befuddled.' def studySpell(spell): print(spell) >>> spell = Accio() >>> spell.execute() Accio >>> studySpell(spell) Summoning Charm Accio No description >>> studySpell(Confundo()) Confundus Charm Confundo Causes the victim to become confused and befuddled. >>> print(spell.incantation) Accio吗？

var html = html + "<tr>\n" + "<td style='text-align: center; background-color: #FFCE43;
'> </br>" + $(n).find("Julio").text() + " <img   style = 'cursor: pointer;' onclick='myFunction(\""+a+"\", \""+b+"\")' src='add.png'></td> </tr>";

如果你不理解我的观点，请告诉我，我会尝试传播更多内容。

Answer 1

import java.util.Arrays; import java.util.regex.Matcher; import java.util.regex.Pattern; /** * Created by Rituraj_Jain on 7/14/2017. */ public class Main { private static final Pattern pattern = Pattern.compile("(\\S)-(\\S)"); private static final String input = "Test-TestBad-ManRituRaj-Jain"; public static void main(String[] args) { Matcher matcher = pattern.matcher(input); String s = matcher.replaceAll("$1 $2"); System.out.println(s); System.out.println(input.replaceAll(pattern.pattern(), "$1 $2")); } public static void main1(String[] args) { Matcher matcher = pattern.matcher(input); StringBuffer finalString = new StringBuffer(); while(matcher.find()){ String replace = matcher.group().replace("-", " "); matcher.appendReplacement(finalString, replace); } matcher.appendTail(finalString); System.out.println(input); System.out.println(finalString.toString()); } }函数不会“分配”studySpell变量（全局变量）。它创建一个新的本地变量（也称为spell），它隐藏全局spell变量，并在函数执行完毕后消失。

Answer 2

要实现您想要的功能，您必须重新分配变量，然后执行方法：

spell = Accio()
spell.execute()
studySpell(spell)
studySpell(Confundo())
spell = Confundo()
print(spell.incantation)

Accio
Summoning Charm Accio
No description
Confundus Charm Confundo
Causes the victim to become confused and befuddled.
Confundo

您发布的代码正在按原样运行。

Answer 3

class Spell:
  
  def __init__(self, incantation, name):
    self.name = name
    self.incantation = incantation

  def __str__(self):
    return self.name + ' ' + self.incantation + '\n' + 
    self.get_description()

  def get_description(self):
    return 'No description'

  def execute(self):
    print(self.incantation)

class Accio(Spell):

  def __init__(self):
    Spell.__init__(self, 'Accio', 'Summoning Charm')

class Confundo(Spell):

  def __init__(self):
    Spell.__init__(self, 'Confundo', 'Confundus Charm')

  def get_description(self):
    return 'Causes the victim to become confused and befuddled.'

  def study_spell(spell):
    print(spell)

spell = Accio()
spell.execute()
study_spell(spell)
study_spell(Confundo())
print(spell.incantation)

python中的类需要指导

3 个答案: