我正在尝试将 JSF Web应用程序与 Spring集成 安全即可。
目前我正在通过一种方法登录:在此内部进行宣传 方法并根据用户重定向到目标页面。
登录页面(login.xhtml):
<h:form id="login">
<h:outputLabel for="email" value="E-mail: "/>
<p:inputText id="email" value="#{loginManagedBean.usuario.email}" required="true"/>
<p:message for="email"/>
<h:outputLabel for="pass" value="Contraseña: "/>
<p:password id="pass" value="#{loginManagedBean.usuario.password}" required="true"/>
<p:message for="pass"/>
<!-- <input type="hidden" name="${_csrf.parameterName}" value="${_csrf.token}"/> -->
<p:commandButton value="Login" update="@form" action="#{loginManagedBean.autenticar()}"/>
</h:form>
loginManagedBean.autenticar()(进行身份验证和重定向的方法):
如何替换此页面和方法以使用SpringSecurity?
SpringSecurityConfig:
@Override
protected void configure(HttpSecurity http) throws Exception {
//.csrf() is optional, enabled by default, if using WebSecurityConfigurerAdapter constructor
// Have to disable it for POST methods:
// http://stackoverflow.com/a/20608149/1199132
http.csrf().disable();
// Logout and redirection:
// http://stackoverflow.com/a/24987207/1199132
http
.logout()
.logoutRequestMatcher(new AntPathRequestMatcher("/logout"))
.deleteCookies("JSESSIONID")
.invalidateHttpSession(true)
.logoutSuccessUrl("/login.xhtml");
http
.authorizeRequests()
//Permit access for all to error and denied views
.antMatchers("/WEB-INF/errorpages/general.xhtml", "/WEB-INF/errorpages/accessDenied.xhtml", "/WEB-INF/errorpages/expired.html", "/login.xhtml")
.permitAll()
// Only access with admin role
.antMatchers("/admin/**")
.hasRole("ADMIN")
//Permit access only for some roles
.antMatchers("/alumno/**")
.hasRole("ALUMNO")
//Permit access only for some roles
.antMatchers("/profesor/**")
.hasRole("PROFESOR")
//If user doesn't have permission, forward him to login page
.and()
.formLogin()
.loginPage("/login.xhtml")
.usernameParameter("login:email")
.passwordParameter("login:pass")
.loginProcessingUrl("/login") //
.defaultSuccessUrl("/admin/homeAdmin.xhtml")
.and()
.exceptionHandling()
.accessDeniedPage("/WEB-INF/errorpages/accessDenied.xhtml");
}
答案 0 :(得分:2)
我宁愿不使用JSF进行身份验证,而是使用普通的HTML表单(having configured之前的身份验证入口点):
<form action="#{request.contextPath}/j_spring_security_check"
method="post">
<h:panelGrid styleClass="centered tight-grid" columns="2">
<p:outputLabel>Usuario</p:outputLabel>
<input type="text" id="username" name="username"
required="required" />
<p:outputLabel>Contraseña</p:outputLabel>
<input type="password" id="password" name="password"
required="required" />
</h:panelGrid>
<h:panelGrid>
<button type="submit">
<span class="ui-button-text">Login</span>
</button>
</h:panelGrid>
</form>
这将对Spring Security身份验证入口点执行POST。然后,一旦用户登录,您就可以使用AuthenticationSuccessHandler
或默认目标网址重定向到您的JSF应用程序。
答案 1 :(得分:0)
登录按钮操作应该首先执行重定向,并将流程传递给spring security。
ExternalContext context = FacesContext.getCurrentInstance().getExternalContext();
RequestDispatcher dispatcher = ((ServletRequest) context.getRequest()).getRequestDispatcher("/login");
dispatcher.forward((ServletRequest) context.getRequest(), (ServletResponse) context.getResponse());
FacesContext.getCurrentInstance().responseComplete();