Xcode错误＆＃34;预期＆＃39; {＆＃39;在函数声明体中＃34;

Question

我已经尝试了一切，但我无法弄清楚错误。

import Foundation
import Firebase

struct User {
    var email: String!
    var firstname: String
    var lastname: String
    var uid: String!
    var profilePictureUrl: String
    var country: String
    var ref: FIRDatabaseReference!
    var key: String = ""

    init(email: String, firstname: String, lastname: String, uid: String, profilePictureUrl: String, country: String) {
        self.email = email
        self.firstname = firstname
        self.lastname = lastname
        self.profilePictureUrl = profilePictureUrl
        self.country = country
        self.ref = FIRDatabase.database().reference()
    }

    func toAnyObject() -> [String: Any] {
        return ["email": email, "firstname": firstname, "lastname": lastname, "country": country, "uid": uid, "profilePictureUrl": profilePictureUrl]
    }
}       

错误在函数toAnyObject中。

Answer 1

你的函数返回[String：Any]。但是，它的值不是Any。可以像以下一样简单地进行编辑。

func toAnyObject() -> [String: Any] {
        return ["email": email, "firstname": firstname, "lastname": lastname, "country": country, "uid": uid, "profilePictureUrl": profilePictureUrl] as [String : Any]

希望它可以帮助您修复问题。