第一个循环

Question

我的代码中有两个循环，我希望第二个循环继续（转到第一个）基本上重新启动程序。

第一个循环

words = []

while True:
    new_item = input("Enter words to select from and type END when you have entered all words: ")
    if new_item == "END":
        break
    words.append(new_item)

chosen = random.choice(words)
length = len(words)
print("Your list is", length, "items long\n" "The randomly chosen word is: ", chosen)

第二个循环

while True:
    option = input("again? (y / n): ")
    if option == "y":
        continue 
    else:
        break

如果用户按下＆＃34; y＆＃34;循环将继续，并再次输入答案。但是，我希望它继续第一个循环（重新启动程序）。如果有任何解决方案或更简单的方法，请帮助。

p.s new to python

Answer 1

为了简单起见，我建议丢弃第二个while循环（你好像是为了回到第一个循环而启动它），并将你的第一个循环嵌套在一个更大的，条件控制的循环中。使用默认值在“master”之外定义option。虽然option保留此值，但您将继续循环。

option = 'y'

while option.lower() in {'y', 'ye', 'yes'}:  
    words = []
    while True:
        new_item = input("Enter words to select from and type END when you have entered all words: ")
        if new_item == "END":
            break
        words.append(new_item)

    chosen = random.choice(words)
    length = len(words)
    print("Your list is", length, "items long\n" "The randomly chosen word is: ", chosen)

    option = input("again? (y / n): ")

Answer 2

将游戏定义为函数game()，并在“第二个”while循环中调用它。如果用户输入“y”，则继续循环调用game() agian，如果用户输入“n”则中断。

def game():
  words = []
  while True:
      new_item = input("Enter words to select from and type END when you have entered all words: ")
      if new_item == "END":
          break
      words.append(new_item)

  chosen = random.choice(words)
  length = len(words)
  print("Your list is", length, "items long\n" "The randomly chosen word is: ", chosen)


while True:
    game()
    option = input("again? (y / n): ")
    if option == "y":
        continue 
    else:
        break

Answer 3

嵌套循环。您正在模拟python中的do-while循环，它在语法时没有native do。以下是非常常见的。

while True:

   # makes empty list for words.
   words = []

    # user enters n words before user enters END
    while True:

        new_item = input("Enter words to select from and type END when you have entered all words: ")

        if new_item == "END":
            # breaks out of inner loop and shows output
            break

        words.append(new_item)

    # show output
    chosen = random.choice(words)
    length = len(words)
    print("Your list is", length, "items long\n" "The randomly chosen word is: ", chosen)

    # ask user for again
    option = input("again? (y / n): ")

    if option == "y":  
        # returns to top of outer loop, and empty words array  
        continue

    else:
        # ends outer loop
        break

如何在python中继续前一个循环

第一个循环

第二个循环

3 个答案: