Question

从根本上说，我想从IntentService建立一个Activity的回调。我的问题与这里回答的问题非常相似：

但是，在答案代码中，活动代码被视为实现ResultReceiver。除非我遗漏了什么，否则ResultReceiver实际上是一个类，所以它无法执行此实现。

基本上，我问的是将ResultReceiver连接到该服务的正确方法是什么。我对Handler和ResultReceiver概念感到困惑。任何工作示例代码都将受到赞赏。

Answer 1

您需要从中扩展自定义resultreceiver类 ResultReceiver
然后在您的活动中实现resultreceiver接口

将自定义resultreceiver对象传递给intentService并在其中 intentservice只是获取接收器对象并调用 receiver.send（）函数将任何内容发送到调用活动中捆绑对象。

这里是customResultReceiver类：

 public class MyResultReceiver extends ResultReceiver {

    private Receiver mReceiver;

    public MyResultReceiver(Handler handler) {
        super(handler);
        // TODO Auto-generated constructor stub
    }

    public interface Receiver {
        public void onReceiveResult(int resultCode, Bundle resultData);

    }

    public void setReceiver(Receiver receiver) {
        mReceiver = receiver;
    }

    @Override
    protected void onReceiveResult(int resultCode, Bundle resultData) {

        if (mReceiver != null) {
            mReceiver.onReceiveResult(resultCode, resultData);
        }
    }

}

在您的活动中实现Myresultreceiver.receiver接口，创建一个类变量

Public MyResultReceiver mReceiver;

在onCreate中初始化此变量：

mReceiver = new MyResultReceiver(new Handler());

mReceiver.setReceiver(this);

通过以下方式将此mReceiver传递给intentService：

intent.putExtra("receiverTag", mReceiver);

并在IntentService中获取，如：

ResultReceiver rec = intent.getParcelableExtra("receiverTag");

并使用rec as：

Bundle b=new Bundle();
rec.send(0, b);

这将在活动的onReceiveResult中收到。您可以在以下网址查看完整代码：IntentService: Providing data back to Activity

编辑：您应该在onResume中调用setReceiver（this），在onPause（）中调用setReceiver（null）以避免泄漏。

Answer 2

通过子类覆盖方法。它不一定是一个接口来做到这一点。

例如：

intent.putExtra(StockService.REQUEST_RECEIVER_EXTRA, new ResultReceiver(null) {
    @Override
    protected void onReceiveResult(int resultCode, Bundle resultData) {
        if (resultCode == StockService.RESULT_ID_QUOTE) {
            ...
        }
    }
});

Answer 3

我创建了一个演示如何使用ResultReceiver。

的简单示例

<强> MainActivity ：

public class MainActivity extends AppCompatActivity {

    private final static String TAG = MainActivity.class.getSimpleName();

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

        Intent serviceIntent = new Intent(this, MyService.class);
        serviceIntent.putExtra("logName", "MAIN_ACTIVITY");
        serviceIntent.putExtra(MyService.BUNDLED_LISTENER, new ResultReceiver(new Handler()) {
            @Override
            protected void onReceiveResult(int resultCode, Bundle resultData) {
                super.onReceiveResult(resultCode, resultData);

                if (resultCode == Activity.RESULT_OK) {
                    String val = resultData.getString("value");
                    Log.i(TAG, "++++++++++++RESULT_OK+++++++++++ [" + val + "]");
                } else {
                    Log.i(TAG, "+++++++++++++RESULT_NOT_OK++++++++++++");
                }
            }
        });
        startService(serviceIntent);
    }
}

<强>为MyService ：

public class MyService extends Service {

    private final static String TAG = MyService.class.getSimpleName();
    public final static String BUNDLED_LISTENER = "listener";

    @Override
    public void onCreate() {
        super.onCreate();

    }

    @Override
    public int onStartCommand(Intent intent, int flags, int startId) {

        String logName = intent.getStringExtra("logName");
        ResultReceiver receiver = intent.getParcelableExtra(MyService.BUNDLED_LISTENER);

        Bundle bundle = new Bundle();
        bundle.putString("value", "30");
        receiver.send(Activity.RESULT_OK, bundle);
        return Service.START_NOT_STICKY;
    }

    @Nullable
    @Override
    public IBinder onBind(Intent intent) {
        return null;
    }

}

Answer 4

我现在会用EventBus来做这件事

https://github.com/google/guava/wiki/EventBusExplained

Answer 5

在android中使用Resulteceiver

创建SomeResultReceiver从resultReceiver扩展
使用on方法创建接口someReceiver，例如onReceivResult（int resultCode，Bundle resultData）;

3.在someResultreceiver中使用someReceiver

create someService扩展了IntentService并使用someresultReceiver.send（）方法将服务的结果发送到someOne类（例如：MyActivity）
在活动

6.在MyActivity类和setreceiver

使用Intent的startService和putExtra someResultreceiver instanse

了解更多详情ResultReceiver Class请参阅enter link description here

在Android中使用ResultReceiver

5 个答案: