Question

如果您有一个地址概念（如所示here），那么您如何编写黄瓜功能来解释资产上所需的地址概念？我看到如何使用factory.newConcept（）使用mocha.js示例，但是可以使用黄瓜来解决这个问题吗？

  And I have added the following assets of type org.acme.Address
      | addressId   | street1         | city    | state    | zipcode  |
      | AddressA    | 123 West 3rd   | Anywhere  | Texas    | 12345    |
      | AddressB    | 123 West 3rd | Anywhere  | Texas    | 12345   |
  And I have added the following assets of type org.acme.Delivery
      | loadId   | start    | end |
      | 1        |  AddressA  | AddressB    |
      | 2        | AddressA  | AddressB    |

模型定义：

concept Address {
  o String street1
  o String street2 optional
  o String city
  o String state
  o String zipcode
  o Double latitude optional
  o Double longitude optional
}

asset Delivery identified by loadId {
  o String loadId
  o Address start
  o Address end
}

我已经尝试在start列中传递参数哈希，但是这不起作用并收到错误

ValidationException：实例org.acme.Delivery＃1中的模型违规 class org.acme.Address的值为addressConcept，期望一个Resource或一个概念。

Answer 1

使用Cucumber测试复杂数据时，需要使用JSON而不是数据表格式。这里有一个例子：

https://github.com/hyperledger/composer/blob/master/packages/composer-cucumber-steps/features/assets.feature#L14

Scenario: given I have added the following assets
    Given I have added the following assets
        """
        [
            {"$class":"org.acme.sample.SampleAsset", "assetId":"1", "owner":"alice@email.com", "value":"10"},
            {"$class":"org.acme.sample.SampleAsset", "assetId":"2", "owner":"bob@email.com", "value":"20"}
        ]
        """
    Then I should have the following assets
        """
        [
            {"$class":"org.acme.sample.SampleAsset", "assetId":"1", "owner":"alice@email.com", "value":"10"},
            {"$class":"org.acme.sample.SampleAsset", "assetId":"2", "owner":"bob@email.com", "value":"20"}
        ]
        """

无论您在哪里看到数据表，都应该能够提供JSON - 包括数组：

https://github.com/hyperledger/composer/blob/master/packages/composer-cucumber-steps/features/assets.feature#L34

import random

print('Welcome to hangman')
print('Type one of the following catagories')

Animal=['Cat','Dog','Bird','Cow','Fish','Lizard']
Clothing=['Shirt','Jeans','Sweatshirt','Shoes','Hat','Scarf']
Weather=['Rain','Snow','Sunny','Sleet','Windy','Stormy']
Colors=['Red','Blue','Green','Purple','Yellow','Grey']

Alphabet= ['a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']

print('Type 1 for Animal, 2 for Clothing, 3 for Weather, 4 for Colors')

catagory=int(input())

while catagory > 4:
    print('Your input isn\'t one of the catagories. Make sure your choice is a number from 1 to 4.')
    print('Try entering again')
    print('Type 1 for Animal, 2 for Clothing, 3 for Weather, 4 for Colors')
    catagory=int(input())

while catagory == 0: 
    print('Your input isn\'t one of the catagories. Make sure your choice _ 
is a number from 1 to 4.')
    print('Try entering again')
    print('Type 1 for Animal, 2 for Clothing, 3 for Weather, 4 for Colors')
    print('')
    print('You have ' + str(numberofguesses) + ' left.  Good luck.'
    catagory=int(input())

if catagory == 1: secretword=random.choice(Animal)
if catagory == 2: secretword=random.choice(Clothing)
if catagory == 3: secretword=random.choice(Weather)
if catagory == 4: secretword=random.choice(Colors)

hiddenword = ('?'*len(secretword))

print('')
print('The word you\'re after is ' + hiddenword)
print('')
print('Type one of the following letters, it must be lowercase.')
print(Alphabet)

i = input()

while numberofguesses != 0:

    if i in secretword:
        Alphabet.remove(i)
        print('')
        print('You guessed correctly')
        list(hiddenword)
        hiddenword=[i if x==str("?") else x for x in hiddenword]
        hiddenguessed= ''.join(hiddenword)
        print('Here is what you have so far '+ str(hiddenguessed))
        print('')
        print('Avalable letters left')
        print(Alphabet)      
        print('Guess another letter')
        i=input()

    else:
        numberofguesses = numberofguesses - 1
        Alphabet.remove(i)
        print('')
        print("You guessed wrong")
        print("")
        list(hiddenword)
        hiddenword=[i if x==str("?") else x for x in hiddenword]
        hiddenguessed= ''.join(hiddenword)
        print('Here is what you have so far '+ str(hiddenguessed))
        print('')
        print('You now have '+str(numberofguesses)+' guesses left.')
        print('Here is what you have so far '+ str(hiddenguessed))
        print('')
        print('Type one of the following letters, it must be lowercase.')
        print(Alphabet)
        i=input()
else:
    Print('Congrats you have won the game.  ' + _ 
str(hiddenguessed) + ' was the secret word')

Answer 2

西蒙的答案很好，但实际上并没有回答被问到的问题（尽管它确实在某种程度上回答了问题）。

如果可以，我想采取刺戳（我假设org.acme是名称空间）：

你需要的小黄瓜看起来像这样：

Scenario: given I have added the following asset
    Given I have added the following asset
    """
    {"$class":"org.acme.Delivery", "loadId":"1", "start":{"$class":"org.acme.Address", "addressId":"AddressA", "street1":"123 West 3rd", "city":"Anywhere", "state": "Texas", "zipcode":"12345"}, "end":{"$class":"org.acme.Address", "addressId":"AddressB", "street1":"123 West 3rd", "city":"Anywhere", "state": "Texas", "zipcode":"12345"}}
    """
    Then I have added the following asset
    """
    {"$class":"org.acme.Delivery", "loadId":"1", "start":{"$class":"org.acme.Address", "addressId":"AddressA", "street1":"123 West 3rd", "city":"Anywhere", "state": "Texas", "zipcode":"12345"}, "end":{"$class":"org.acme.Address", "addressId":"AddressB", "street1":"123 West 3rd", "city":"Anywhere", "state": "Texas", "zipcode":"12345"}}
    """

使用标准JSON嵌套语法注意嵌套 Address对象。

同样，我认为Simon的答案很好，但如果你不是JSON专家，那么将他的答案（针对一个完全不同的场景）扩展到被问到的答案可能会有挑战性。

除了起始地址和结束地址相同（并且12345在德克萨斯州不是有效的邮政编码）之外，这应该回答所提出的确切问题。

- JSP

使用Cucumber在Hypledger Composer中测试Concept类型

2 个答案: