Question

我需要快速报告员工演示者及其客户教室出勤率，并且我试图在SQL中找出正确的查询（对于SQL Server）。

客户端是针对类单独安排的，因此在表tSchedule中，每一行都有一个类名，类的时间和日期，客户端名称，类主持人的名称以及客户端的名称。出勤状态（例如，＆＃39;现在＆＃39;缺席＆＃39;缺席＆＃39;缺席＆＃39;，＆＃39;迟到＆＃39;等等。）

所以我需要一个SQL查询，它将为每个演示者输出一行，其中包含在给定日期范围内在该演示者类中安排的客户端总数，即实际显示的总数（即出席状态为“出席状态”或“缺席出借”（＃）;以及出现或出现的总数的百分之几＆＃34;客户代表。

在下面的每个回复中添加一些细节：

tSchedule

class            class_date     Employee_id     client_id       attendance_status
Basket Weaving   2017-07-13     231             712             Present
Basket Weaving   2017-07-13     231             121             Present
Basket Weaving   2017-07-13     231             186             Absent
Basket Weaving   2017-07-13     231             666             Absent
Juggling         2017-07-13     900             111             Present
Juggling         2017-07-13     900             222             Present
Juggling         2017-07-13     900             333             Present
Juggling         2017-07-13     900             712             Absent w/Excuse



Expected Result of Query:

Employee_id Clients Scheduled   Clients Present or Excused  Attendance Rate
231         4                   2                           50%
900         4                   4                           100%

（附录）好吧，我最终使用（下面）的查询有效，但它很难看，我确定不理想。如果有人知道获得相同结果的最优雅方式，我会非常感激。（@ param1和@param2是用户输入的日期，表示所需时间跨度的开始和结束日期）

Select
   pl.emp_id
   ,e.last_name + ', ' + e.first_name as facilitator
   ,count(pl.emp_id) as total_Count
   ,(select count(*) from planner where emp_id = pl.emp_id
       and visit_status in ('ARRIVED', 'PRESENT WITH JS', 'PRESENT NO JS')
       and plan_date >= @param1
       and plan_date <= @param2) as attended_Count
   ,cast(cast((select count(*) from planner where emp_id = pl.emp_id
       and visit_status in ('ARRIVED', 'PRESENT WITH JS','PRESENT NO JS')
       and plan_date >= @param1
       and plan_date <= @param2) as float) / cast((select count(*) from
       planner where emp_id = pl.emp_id
       and plan_date >= @param1
       and plan_date <= @param2) as float) * 100 as decimal (18,2)) as attendance_percent
from planner pl inner join employees e on pl.emp_id = e.emp_id
where pl.program_id = 2
    and pl.visittype_id in (42,173)
    and plan_date >=@param1
    and plan_date <= @param2
group by pl.emp_id, e.last_name + ', ' + e.first_name

Answer 1

select
    status,
    cnt*100.0/total
from 
(select c status,count(*) cnt from attendance c group by c.status),
(select count(*)total from attendance c)

SQL百分比组

1 个答案: