我正在尝试在ListView
中制作可点击的项目,并重新发现此类错误。
ListView chHE = (ListView) findViewById(R.id.lvHE);
ArrayAdapter<String> adapter = new ArrayAdapter<String>(this,
R.layout.support_simple_spinner_dropdown_item, cities);
chHE.setAdapter(adapter);
chHE.getOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long l) {
if (position == 0) {
toast.show();
}
}
});
错误:(52,13)错误:类AdapterView中的方法getOnItemClickListener 不能适用于给定的类型; 必需:没有参数 发现: 原因:实际和正式的参数列表长度不同 其中T是一个类型变量: T扩展了AdapterView类中声明的Adapter
答案 0 :(得分:0)
您应该将getOnItemClickListener
重新加入setOnItemClickListener
ListView lv = getListView();
lv.setOnItemClickListener(new OnItemClickListener()
{
@Override
public void onItemClick(AdapterView<?> adapter, View v, int position,
long arg3)
{
String value = (String)adapter.getItemAtPosition(position);
// assuming string and if you want to get the value on click of list item
// do what you intend to do on click of listview row
}
});
答案 1 :(得分:0)
pow
也许你已经写过一个mastake?change get =&gt; set
答案 2 :(得分:-1)
尝试这样做
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
//doSomeThing
}
});