如何按字段值对mongodb文档进行排序？

Question

假设我有一个带有以下架构的mongodb集合

{ "_id" : "1", "name" : "person1", "description" : "description1" }
{ "_id" : "2", "name" : "person2", "description" : "description2" }
{ "_id" : "3", "name" : "person3", "description" : "description3" }
{ "_id" : "4", "name" : "person1", "description" : "description4" }
{ "_id" : "5", "name" : "person2", "description" : "description5" }
{ "_id" : "6", "name" : "person4", "description" : "description6" }
{ "_id" : "7", "name" : "person3", "description" : "description7" }
{ "_id" : "8", "name" : "person2", "description" : "description8" }
{ "_id" : "9", "name" : "person3", "description" : "description9" }
{ "_id" : "10", "name" : "person1", "description" : "description10" }

我想按照以下顺序按人名值排序

person4

person2

person1

person3

如何将它们变成这种形式？

{ "_id" : "6", "name" : "person4", "description" : "description6" }
{ "_id" : "2", "name" : "person2", "description" : "description2" }
{ "_id" : "8", "name" : "person2", "description" : "description8" }
{ "_id" : "5", "name" : "person2", "description" : "description5" }
{ "_id" : "1", "name" : "person1", "description" : "description1" }
{ "_id" : "4", "name" : "person1", "description" : "description4" }
{ "_id" : "10", "name" : "person1", "description" : "description10" }
{ "_id" : "7", "name" : "person3", "description" : "description7" }
{ "_id" : "3", "name" : "person3", "description" : "description3" }
{ "_id" : "9", "name" : "person3", "description" : "description9" }

以下是SQL世界中的相同场景

+----+---------+---------------+
| id | name    | description   |
+----+---------+---------------+
|  1 | person1 | description1  |
|  2 | person2 | description2  |
|  3 | person3 | description3  |
|  4 | person1 | description4  |
|  5 | person2 | description5  |
|  6 | person4 | description6  |
|  7 | person3 | description7  |
|  8 | person2 | description8  |
|  9 | person3 | description9  |
| 10 | person1 | description10 |
+----+---------+---------------+

所以我使用这个查询

select id, name, description
from test
order by case when name like 'person4' then 1
when name like 'person2' then 2
when name like 'person1' then 3
when name like 'person3' then 4 end

给了我正确的结果

+----+---------+---------------+
| id | name    | description   |
+----+---------+---------------+
|  6 | person4 | description6  |
|  2 | person2 | description2  |
|  8 | person2 | description8  |
|  5 | person2 | description5  |
|  1 | person1 | description1  |
|  4 | person1 | description4  |
| 10 | person1 | description10 |
|  7 | person3 | description7  |
|  3 | person3 | description3  |
|  9 | person3 | description9  |
+----+---------+---------------+

我们是否具有SQL order by case when then语句的等价物？或者在mongodb中实现这一目标的任何解决方案？