这是我从数据库中提取数据的选择ID
HTML
var jsonData = [{"id":"jmbaaaro@kaps.co.ke","passkey":null},{"id":"willson@gmail.com","passkey":"3694"},{"id":"info@llvswaterboard.go.ke","passkey":null},{"id":"rundda@athiwater.com","passkey":"5576"},{"id":"pk@.k.com","passkey":"1835"},{"id":"pkinnyanjui@kaps.co.ke","passkey":null},{"id":"wilsson@gmail.com","passkey":"3694"}{"id":"wycllif@kaps.co.ke","passkey":"2318"},{"id":"wycllif@gmail.com","passkey":"2318"},{"id":"alexx@gmail.com","passkey":"2710"},{"id":"wilsson@gmail.com","passkey":"3694"},{"id":"barbeggambo@gmail.com","passkey":"8917"},{"id":"bachu@gmail.com","passkey":"5857"}]
JSON
var jsonData = JSON.parse(data);
//var jsonData = JSON.parse(s);
var select = $$('#mySelectID');
for (var i = 0; i < jsonData.length; i++) {
var option = $("<option/>").attr("value",jsonData[i].id).text(jsonData[i].id);
select.append(option);
}
$("select#mySelectID").change(function(){
var selectedmail = $("#mySelectID").val();
var s = jsonData.filter(function (e){
return e.id ==='3694';
});
JAVASCRIPT
li.col-sm-3:nth-child(5) {
clear: both;
}
我试图通过密码3694获取值。请协助我是javascript的新手。