Question

以前我在单个类中处理了所有的http请求，但我想将http登录功能移到另一个类但现在我无法访问http客户端response.IsSuccessStatusCode

这是我的原始代码

var http = new HttpClient();
var url = String.Format(shared.AppDetails.domainurl+"/v2auth/default/login");
var response2 = await http.PostAsync(url, credentials);

if (response.IsSuccessStatusCode)
{
    //do after login stuff
}

现在我想将登录逻辑移动到另一个不同文件夹中的类（auth-＆gt; dbhelpers）

class LoginHttp
{
    public static async Task<object> loginAsync(String username, String password)
    {
        var values = new Dictionary<string, string>
        {
            { "username",username },
            { "password", password }
        };
        var credentials = new FormUrlEncodedContent(values);

        var http = new HttpClient();
        var url = String.Format(shared.AppDetails.domainurl + "/v2auth/default/login");
        var response = await http.PostAsync(url, credentials);

        return response;
    }  
}

现在正尝试通过

访问返回的响应

var responsefromhttplogin = auth.dbhelpers.AuthHttp.loginAsync(login_username.Text, login_password.Password);
if (responsefromhttplogin .IsSuccessStatusCode) //this fails
{
    //do after login stuff
}

如何再次获得HttpClient类型的后续响应？我的错误是

Task<Objct> does not contain defination for IsSuccessStatusCode

Answer 1

尝试将代码更改为等待异步方法，如下所示：

tests

现在添加等待后，var responsefromhttplogin = await auth.dbhelpers.AuthHttp.loginAsync(login_username.Text, login_password.Password); if (responsefromhttplogin.IsSuccessStatusCode) { //do after login stuff }应该可以访问。

并且还要更改您的方法以返回responsefromhttplogin.IsSuccessStatusCode而不是Task<HttpResponseMessage>

Answer 2

您将从SELECT opreator.o_name, c1.c_name as dept, c2.c_name as destination, route.fare FROM route JOIN opreator ON route.opreator = opreator.id JOIN city c1 ON route.dep = c1.id JOIN city c2 ON route.dest = c2.id返回Task<object>，以访问您可以使用loginAsync()任务的结果。

我会考虑缩小您从Task.Result返回object的类型。

Answer 3

使您的loginAsync方法返回Task。目前您正在返回一个对象，然后您将可以访问IsSuccessStatusCode

YourClass result = mapper.reader(DeserializationFeature.ACCEPT_SINGLE_VALUE_AS_ARRAY)
                         .forType(YourClass.class)
                         .readValue(json);

}

您还需要在调用方法中使用await，否则您将获得一个任务

class LoginHttp{
public static async Task<HttpResponseMessage> loginAsync(String username, String password)
{
    var values = new Dictionary<string, string>
         {
          { "username",username },
          { "password", password }
        };
    var credentials = new FormUrlEncodedContent(values);

    var http = new HttpClient();
    var url = String.Format(shared.AppDetails.domainurl + "/v2auth/default/login");
    var response = await http.PostAsync(url, credentials);

    return response;
}

Answer 4

根据您的代码判断，您将返回Task<object>

您应该将return response;转换为return (HttpResponseMessage) response;

或将返回类型更改为Task<HttpResponseMessage>

Relevant documentation

C＃从另一个类方法获取http响应

4 个答案: