Question

我有一个代码可以为＆＃34;移动＆＃34;产生所需的输出。它查看每个时期并给我信息的宇宙。我希望有另一个查询产生相同的输出但是对于不同的选择，一个＆＃34;当前＆＃34;宇宙。

当前的Universe会像现在一样进行汇总，但仅适用于数据库中最新日期符合条件的公司。

目前，对于Market_Cap介于2015年0到10000之间的公司等，代码会产生EBIT / Sales 2015，但我宁愿希望它为目前市场营销介于0到10000之间的公司产生EBIT / Sales 2015（最新date_month在Market_Cap）

我正在使用Microsoft SQL Server Management Studio

我试图在总和中插入另一个标准（当时的情况......然后）语法为＆＃34;并且c.company_id在（从Market_cap中选择company_id，其中Market_Cap介于0和10000之间，日期=＆＃39; 2017-06-30））但我收到错误：

无法对包含聚合或子查询的表达式执行聚合函数。

现在代码：

 select m.date_month     
     ,sum(case when y.date_year = 2015 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then n.EBIT end) / sum(case when y.date_year = 2015 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then s.Sales end) as 'EBIT/Sales 2015'  
     ,sum(case when y.date_year = 2016 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then n.EBIT end) / sum(case when y.date_year = 2016 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then s.Sales end) as 'EBIT/Sales 2016'  
     ,sum(case when y.date_year = 2017 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then n.EBIT end) / sum(case when y.date_year = 2017 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 AND mm.Market_Cap between 0 and 10000 then s.Sales end) as 'EBIT/Sales 2017'  
 from  EBIT   as n  
     inner join  Sales   as s on  s.company_id = n.company_id  
                             and s.date_month_id = n.date_month_id  
                             and s.date_year_id = n.date_year_id  
     inner join date_year as y on y.date_year_id = n.date_year_id  
     inner join date_month as m on m.date_month_id = n.date_month_id 
     inner join Market_Cap as mm on mm.Date_Month_Id = n.Date_Month_Id
                             and mm.Company_Id = n.Company_Id
     inner join Company as c on c.Company_Id = n.Company_Id
 where y.date_year between   2015  and   2017     
     and n.EBIT<> 0  
     and s.Sales<> 0 
 group by m.date_month;

正确输出：

Answer 1

此处包含的唯一代码是选择代码，而不是基于市值实际过滤的代码。你想不想改变这些界限：

inner join Market_Cap as mm on mm.Date_Month_Id = n.Date_Month_Id
                         and mm.Company_Id = n.Company_Id

将mm.Date_Month_Id与max(Date_Month_Id)？

进行比较

Answer 2

正确查询（我认为）：

 select m.date_month     
     ,sum(case when y.date_year = 2015 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then n.EBIT end) / sum(case when y.date_year = 2015 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then s.Sales end) as 'EBIT/Sales 2015'  
     ,sum(case when y.date_year = 2016 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then n.EBIT end) / sum(case when y.date_year = 2016 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then s.Sales end) as 'EBIT/Sales 2016'  
     ,sum(case when y.date_year = 2017 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then n.EBIT end) / sum(case when y.date_year = 2017 AND c.Country_Id in (4,5,6) AND c.factSet_Level1_Id between 1 and 100 then s.Sales end) as 'EBIT/Sales 2017'  
 from  EBIT   as n  
     inner join  Sales   as s on  s.company_id = n.company_id  
                             and s.date_month_id = n.date_month_id  
                             and s.date_year_id = n.date_year_id  
     inner join date_year as y on y.date_year_id = n.date_year_id  
     inner join date_month as m on m.date_month_id = n.date_month_id 
     inner join Market_Cap as mm on mm.Date_Month_Id = n.Date_Month_Id
                             and mm.Company_Id = n.Company_Id
     inner join Company as c on c.Company_Id = n.Company_Id
 where y.date_year between   2015  and   2017 and c.Company_Id in (Select Company_Id from Market_Cap Where Market_Cap between 0 and 1000) 
     and n.EBIT<> 0  
     and s.Sales<> 0 
 group by m.date_month
 order by m.Date_Month asc;

SQL -

2 个答案: