Question

我在一个小Javascript上被困了10个小时。我是一个非常年轻的开发人员。我在localStorage中存储了一些位置（JSON），我希望选择具有特定值的所有数据（例如“category = 2”），然后获取纬度和经度的最近位置。

var jsonString = "{
    "version": "1.0.0",
    "places": [
        {
            "id": "564",
            "segment": "Europe (Avenue De L')",
            "adresse": "Avenue De L'Europe 58",
            "enseigne": "Eko Services",
            "responsable": "",
            "tel": "071\/30.70.02",
            "email": "charleroi@ekoservices.be",
            "site": "www.ekoservices.be",
            "categorie": "12",
            "creation": "",
            "latitude": "",
            "longitude": ""
        },
        {
            "id": "565",
            "segment": "Fort (Rue Du)",
            "adresse": "Rue Du Fort 68",
            "enseigne": "ALE Charleroi",
            "responsable": "Mme. Francia Annick (Responsable)",
            "tel": "071\/20.80.90",
            "email": "ale.charleroi@skynet.be",
            "site": "",
            "categorie": "11",
            "creation": "",
            "latitude": "",
            "longitude": ""
        },
        {
            "id": "566",
            "segment": "Beffroi (Rue Du)",
            "adresse": "Rue du Beffroi 30",
            "enseigne": "Le Chien Elegant",
            "responsable": "Mme. Cilli Christine",
            "tel": "071\/30.80.30",
            "email": "lechienelegant@skynet.be",
            "site": "www.lechienelegant.be",
            "categorie": "12",
            "creation": "",
            "latitude": "",
            "longitude": ""
        }
    ]
}  "

//var myData = JSON.parse(localStorage.getItem("placesJSON"));

$(document).ready(function () {

    var distanceObj = [],
        i = 0;

    $.each(myData, function (a, b) {
        distanceObj[i] = { distance: hesapla(9.9608999, 49.7222842, b.places.longitude, b.places.Latitude), location: a };
        ++i;
    });

    distanceObj.sort(function(a,b) {
        return parseInt(a.distance) - parseInt(b.distance)
    });

    $.each(distanceObj, function(a, b) {
        $('#places').append('<li>' + b.location + ': ' + b.distance + 'm</li>');
    });
    
    console.log(distanceObj);

    function hesapla(meineLongitude, meineLatitude, long1, lat1) {
        erdRadius = 6371;

        meineLongitude = meineLongitude * (Math.PI / 180);
        meineLatitude = meineLatitude * (Math.PI / 180);
        long1 = long1 * (Math.PI / 180);
        lat1 = lat1 * (Math.PI / 180);

        x0 = meineLongitude * erdRadius * Math.cos(meineLatitude);
        y0 = meineLatitude * erdRadius;

        x1 = long1 * erdRadius * Math.cos(lat1);
        y1 = lat1 * erdRadius;

        dx = x0 - x1;
        dy = y0 - y1;

        d = Math.sqrt((dx * dx) + (dy * dy));


        return Math.round(d * 1000);
    };

});

<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<div id="places"></div>

感谢您的帮助！

Answer 1

只需遍历数组

x:Key

在localStorage和我的地理定位中获取JSON最近的位置

1 个答案: