Question

我有像

这样的JSON响应

q13 =     {
    multiple = multiple;
    restrict = all;
    title1 = "Board Certification:";
    title2 = "Exp Date:";
    type = "double_text";
    value1 =         (
        "Test Certificate"
    );
    value2 =         (
        "12/14/27"
    );
};

现在在JSON响应中我只需要value1和value2的值，这两个值必须存储在用逗号（，）分隔的单个字符串中。

怎么做？

Answer 1

这样做很简单。如果两个数组中都有多个值。

NSDictionary *dictionary =[your_Json_Object valueForKey:@"q13"];
NSArray *value1Array = [dictionary valueForKey:@"value1"];
NSArray *value2Array = [dictionary valueForKey:@"value2"];

NSMutableString *combinedString = [NSMutableString new];

[value1Array enumerateObjectsUsingBlock:^(NSString *str1, NSUInteger idx, BOOL *stop) {

    NSString * innerCombinedString = [NSString stringWithFormat:@"%@  %@",str1,[value2Array objectAtIndex:idx]];
    [combinedString appendString:innerCombinedString];
    if (idx != value1Array.count) {
      [combinedString appendString:@","];
    }

}];

Answer 2

我只创建两个NSmutabledictionary并获得一个字符串。你有任何疑问让我知道我解释。

 NSMutableDictionary *Dict_Value;
 NSMutableDictionary *Dict_Value1;

 Dict_Value = [[NSMutableDictionary alloc] init];

[Dict_Value setObject:@"FirstDict" forKey:@"One"];
[Dict_Value setObject:@"FirstDict" forKey:@"Two"];
[Dict_Value setObject:@"FirstDict" forKey:@"Three"];
[Dict_Value setObject:@"FirstDict" forKey:@"Four"];

Dict_Value1 = [[NSMutableDictionary alloc] init];


[Dict_Value1 setObject:@"2Multiple1" forKey:@"2One"];
[Dict_Value1 setObject:@"2Multiple2" forKey:@"2Two"];
[Dict_Value1 setObject:@"2Multiple3" forKey:@"2Three"];
[Dict_Value1 setObject:@"2Multiple4" forKey:@"2Four"];


NSString *string= [NSString stringWithFormat:@"Dict1 %@, Dict2 %@",[Dict_Value valueForKey:@"Value1"],[Dict_Value1 valueForKey:@"Value2"]];

Answer 3

请考虑以下是您在JSON中获得的词汇：

 NSMutableDictionary *dicMain = [NSMutableDictionary new];
    dicMain[@"multiple"] = @"multiple";
    dicMain[@"restrict"] = @"all";
    dicMain[@"title1"] = @"Board Certification:";
    dicMain[@"title2"] = @"Exp Date:";
    dicMain[@"type"] = @"double_text";

    dicMain[@"value1"] = [NSArray arrayWithObject:@"Test Certificate"];
    dicMain[@"value2"] = [NSArray arrayWithObject:@"12/14/27"];

以下是将值转换为一个字符串的逻辑：

NSArray *aryValue1 = [dicMain valueForKey:@"value1"];
NSArray *aryValue2 = [dicMain valueForKey:@"value2"];
NSString *strFinalString = [NSString stringWithFormat:@"%@ %@",[aryValue1 componentsJoinedByString:@" "],[aryValue2 componentsJoinedByString:@" "]];

NSLog(@"%@",strFinalString);

如何将两个字典值转换为单个字符串？

3 个答案: