如何使用Django但没有rest-framework执行以下任务? 例如,如何将用户保存到我的模型中? 这是我目前的代码:
from rest_framework import serializers
from .models import User,Blog
class UserSerializer(serializers.ModelSerializer):
class Meta:
model = User
fields = ('std_num','password' , 'first_name', 'last_name', 'email')
from rest_framework.views import APIView
from rest_framework.response import Response
from rest_framework import status
from .models import User
from .serializers import UserSerializer
class register (APIView):
def post(self, request):
serializer = UserSerializer(data = request.data)
if serializer.is_valid():
serializer.save()
return Response(serializer.data, status=111)
return Response(serializer.errors, status=100)
答案 0 :(得分:0)
import json
from .models import User
from django.http import HttpResponse
from django.views import View
class register(View):
def post(self, request):
if not request.POST.get('password') or not request.POST.get('email'):
#Do checking for other values
return_dict = {'status':False,'code':111}
else:
user_obj =User.objects.create(email=request.POST.get('email'),
password=request.POST.get('password'))
#save the needed values
user_obj.save()
return_dict = {'status':True,'code':100}
return HttpResponse(json.dumps(return_dict))
检查api响应中的“代码”或“状态”值以执行相关操作
答案 1 :(得分:0)
您无需显式创建用户对象。此作业通过调用 serializer.save()完成。您自己创建用户效率很低。 Django 提供内置功能,但如果您愿意,可以覆盖它。