Question

在对象上进行SequelizeJS查询并且包含具有所属关系的关系时，是否有办法让包含的属性不返回带有结果的关联映射对象？

即：

Users.findAll({include: [{model: Role, as: 'roles'}]})

//yields objects of the following form
user: {
    username: 'test',
    roles: [
        {
           name: 'user',
           UserRoles: {userId: 1, roleId: 1} //<--I do not want this
        }
    ]        
}

Answer 1

在github评论中找到了解决方案：https://github.com/sequelize/sequelize/issues/4074#issuecomment-153054311

要旨：

Users.findAll({
    include: [
        {
            model: Role, 
            as: 'roles',
            through: {attributes: []} //<-- this line will prevent mapping object from being added
        }
    ]
});

Answer 2

您可以尝试指定attributes属性。

所以要包括字段说a，b，c你添加

attributes: ['a', 'b','c']

排除他们

attributes:{exclude:['a', 'b','c']}

所以findAll看起来像

Model.someModel.findAll({
  where: // some condition
  include: // some other model
  attributes: // some fields
})

您还可以在include子句

中指定属性

Sequelize排除了属于多对的映射对象

2 个答案: