Question

我正在尝试选择下面有3个唯一GUID的3行：

  SELECT 
    number                                  AS 'ID #', 
    line                                    AS 'Line #', 
    network                                 AS Network,
    FORMAT(SUM(totalCost), N'c', 'en-US')   AS Total 
  FROM 
    theLine 
  WHERE 
    theGuid = '32e1319d-8842-4b98-9a66-c1e694417528' 
  AND 
    theGuid = '61e819a8-a37a-4105-aab0-e34df31d992d' 
  AND
    theGuid = '6675811d-9a32-4b62-a003-87344af03d6b' 
  GROUP BY 
    number, line, network

然而，当我运行此查询时，我没有得到任何记录。如果我只是执行 1 WHERE子句，那么我会获得与该GUID相关的记录，但不再呈现任何结果。

但我需要它做的是：

------------------------------------
|ID #  |Line # |Network |Total     |
------------------------------------
|1     |1      |USASV   |$5,000.00 |
|2     |1      |FJESC   |$4,920.00 |
|3     |1      |RTDEW   |$598.00   |

那么，我做错了什么？

Answer 1

您不能在同一行中拥有3个不同的值。将AND更改为OR或使用IN运算符。

  SELECT 
    number                                  AS 'ID #', 
    line                                    AS 'Line #', 
    network                                 AS Network,
    FORMAT(SUM(totalCost), N'c', 'en-US')   AS Total 
  FROM 
    theLine 
  WHERE 
    theGuid = '32e1319d-8842-4b98-9a66-c1e694417528' 
  OR
    theGuid = '61e819a8-a37a-4105-aab0-e34df31d992d' 
  OR
    theGuid = '6675811d-9a32-4b62-a003-87344af03d6b' 
  GROUP BY 
    number, line, network

或者：

  SELECT 
    number                                  AS 'ID #', 
    line                                    AS 'Line #', 
    network                                 AS Network,
    FORMAT(SUM(totalCost), N'c', 'en-US')   AS Total 
  FROM 
    theLine 
  WHERE 
    theGuid IN (
                '32e1319d-8842-4b98-9a66-c1e694417528',
                '61e819a8-a37a-4105-aab0-e34df31d992d',
                '6675811d-9a32-4b62-a003-87344af03d6b' 
               )
  GROUP BY 
    number, line, network

Answer 2

在WHERE子句中使用OR而不是AND

Answer 3

这是IN的一个很好的示例用例，但我不确定为什么你有GROUP BY

SELECT 
    number                                  AS 'ID #', 
    line                                    AS 'Line #', 
    network                                 AS Network,
    FORMAT(SUM(totalCost), N'c', 'en-US')   AS Total 
 FROM 
    theLine 
 where theGuid in ('32e1319d-8842-4b98-9a66-c1e694417528','61e819a8-a37a-4105-aab0-e34df31d992d','6675811d-9a32-4b62-a003-87344af03d6b' )
GROUP BY 
number, line, network

MS SQL 2014 TSQL拉3条记录

3 个答案: