Question

我正在尝试启动并运行已经适用于其他人的API（当然，我现在无法咨询）。我得到一个特定端点的错误：

TypeError: dict_values([
{'unregistered_users': 2, 'group_name': 'a', 'registered_users': 9, 'total_users': 11}, 
{'unregistered_users': 0, 'group_name': 'b', 'registered_users': 4, 'total_users': 4},
{'unregistered_users': 0, 'group_name': 'c', 'registered_users': 4, 'total_users': 4}, 
{'unregistered_users': 4, 'group_name': 'd', 'registered_users': 5, 'total_users': 9}, 
{'unregistered_users': 0, 'group_name': 'e', 'registered_users': 7, 'total_users': 7}, 
{'unregistered_users': 0, 'group_name': 'f', 'registered_users': 7, 'total_users': 7}]) is not JSON serializable

据我所知，这是有效的JSON，没有理由不能将其序列化。我已经仔细研究了其他关于缺少JSON可串行性的SO问题，并且找不到任何关于为什么这不起作用的提示。我的堆栈跟踪：

  File "/Users/AJ/code/my_app/events/views/event_views.py", line 50, in get
    return JsonResponse(event)
  File "/usr/local/lib/python3.5/site-packages/django/http/response.py", line 530, in __init__
    data = json.dumps(data, cls=encoder, **json_dumps_params)
  File "/usr/local/Cellar/python3/3.5.2/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/__init__.py", line 237, in dumps
    **kw).encode(obj)
  File "/usr/local/Cellar/python3/3.5.2/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/encoder.py", line 198, in encode
    chunks = self.iterencode(o, _one_shot=True)
  File "/usr/local/Cellar/python3/3.5.2/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/encoder.py", line 256, in iterencode
    return _iterencode(o, 0)
  File "/usr/local/lib/python3.5/site-packages/django/core/serializers/json.py", line 121, in default
    return super(DjangoJSONEncoder, self).default(o)
  File "/usr/local/Cellar/python3/3.5.2/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/encoder.py", line 179, in default
    raise TypeError(repr(o) + " is not JSON serializable")

使用OS X，Python 3.5，Django 1.11和带有UTF-8编码FWIW的Postgres DB。不知道在哪里继续进行故障排除。

抛出错误的代码：

from django.http import JsonResponse, HttpResponseNotFound, HttpResponseForbidden
...
@method_decorator([need_jwt_verification, csrf_exempt], name="dispatch")
class EventController(View):
    def get(self, request, id):
        event = self.eventService.get_event_details(id)
        ...
        return JsonResponse(event)

Django的JsonResponse不是JSON可序列化的 - 为什么？

0 个答案: