C#Interactive:托管流程退出,退出代码为-1073741819

时间:2017-07-12 15:04:03

标签: c# c#-interactive

我启动了Visual Studio 2017,并打开了C#Interactive。 当我尝试使用以下代码时,我收到了一条相当特殊的错误消息:

> System.Runtime.Serialization.FormatterServices.GetUninitializedObject(((object)typeof(object)).GetType())
Hosting process exited with exit code -1073741819.
Loading context from 'CSharpInteractive.rsp'.
> 

所以我尝试用try / catch包围它,它似乎工作(不退出过程):

> try { System.Runtime.Serialization.FormatterServices.GetUninitializedObject(((object)typeof(object)).GetType()); } catch (Exception ex) { }
> 

然后我试着获得Exception的类型:

> try { System.Runtime.Serialization.FormatterServices.GetUninitializedObject(((object)typeof(object)).GetType()); } catch (Exception ex) { WriteLine(ex.GetType()); }
> 

没有输出?很奇怪......我尝试输出"未初始化的对象",它又开始退出该过程...

> try { WriteLine(System.Runtime.Serialization.FormatterServices.GetUninitializedObject(((object)typeof(object)).GetType())); } catch (Exception ex) { WriteLine(ex.GetType()); }
Hosting process exited with exit code -1073741819.
Loading context from 'CSharpInteractive.rsp'.
> 

捕捉一切都不起作用:

> try { WriteLine(System.Runtime.Serialization.FormatterServices.GetUninitializedObject(((object)typeof(object)).GetType())); } catch { }
Hosting process exited with exit code -1073741819.
Loading context from 'CSharpInteractive.rsp'.
> 

有人可以解释一下这里发生了什么吗?

0 个答案:

没有答案