Question

我知道这很简单，但我不记得应该怎么做。

基本上，我希望函数select_data返回的结果是像：

['something','something_a','something_b']

而不喜欢，目前正在返回的内容：

[(u'something',), (u'something_a',)(u'something_b',)]

以下，我使用的代码块：

import sqlalchemy
from sqlalchemy import Table, exc, and_
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker

from configurations import config_loader

hostname = config_loader.get('db_config', 'hostname')
db_name = config_loader.get('db_config', 'db_name')
db_port = config_loader.get('db_config', 'db_port')
login = config_loader.get('db_config', 'db_login')
pwd = config_loader.get('db_config', 'db_pwd')
sample_table = config_loader.get('db_tables', 'some_table')


con_string = 'mysql+mysqlconnector://{login}:{passwd}@{hostname}:{port}/{db}'

engine_str = con_string.format(
    login=login, passwd=pwd, hostname=hostname, port=db_port, db=db_name
)

try:
    engine = sqlalchemy.create_engine(engine_str, echo=False)
    session = sessionmaker(bind=engine)
    connection = engine.connect()
    session = session(bind=connection)
    Base = declarative_base()
except exc.SQLAlchemyError:
    raise


def select_data(server):
    t = Table(some_table, Base.metadata, autoload_with=engine)
    stm = session.query(t.c.data_name).filter(
        t.c.server == server
    )
    return stm.all()

Answer 1

您的代码返回list的tuples。您应该提取元组，添加以下代码：

raw_data = select_data(server)
data = [item[0] for item in raw_data]

提取的另一种方法：

import operator

raw_data = select_data(server)
data = map(operator.itemgetter(0), raw_data)

有关SQLAlchemy的更多信息。

如何从sqlalchemy中删除查询结果的括号

1 个答案: