使用mssql查询选择不同的前两个八位字节

Question

我的MS SQL表中的示例数据

Column Name: IPAddress
1.18.120.201,192.178.120.201
192.168.120.202,192.188.120.202,192.198.120.202
192.168.121.3
192.169.121.50
1.1.1.1
11.11.11.11

作为我想要的输出

192.168
192.169
192.178
192.188
192.198
1.18
1.1
11.11

IPAddress列也可以有多个IP地址值。

我写了类似下面的内容。请告诉我在查询中需要做出哪些更改

SELECT
    SUBSTRING(IPAddress, 1, LEN(IPAddress) - CHARINDEX('.',REVERSE(IPAddress))),
    COUNT(*)
FROM
    ...
GROUP BY
    SUBSTRING(IPAddress, 1, LEN(IPAddress) - CHARINDEX('.',REVERSE(IPAddress)))

Answer 1

在下面试试

 ;WITH cte(IPAddress)
AS
(
SELECT '1.18.120.201,192.178.120.201'                       UNION ALL
SELECT '192.168.120.202,192.188.120.202,192.198.120.202'    UNION ALL
SELECT '192.168.121.3'                                      UNION ALL
SELECT '192.169.121.50'                                     UNION ALL
SELECT '1.1.1.1'                                            UNION ALL
SELECT '11.11.11.11'                        
)
SELECT DISTINCT SUBSTRING(IPAddress, 0, CHARINDEX('.', IPAddress, CHARINDEX('.', IPAddress) + 1)) AS IPAddress
FROM (
    SELECT  Split.a.value('.', 'VARCHAR(1000)') AS IPAddress
    FROM (
        SELECT CAST('<S>' + REPLACE(IPAddress, ',', '</S><S>') + '</S>' AS XML) AS IPAddress
        FROM cte
        ) AS A
    CROSS APPLY IPAddress.nodes('/S') AS Split(a)
    ) DT
ORDER BY 1 DESC

预期结果

IPAddress
---------
192.198
192.188
192.178
192.169
192.168
11.11
1.18
1.1

Answer 2

create table #t(IPAddress varchar(15))
insert into #t(IPAddress)
select '192.168.120.201'
union all select '192.178.120.201'
union all select '192.168.120.202'
union all select '192.188.120.202'
union all select '192.198.120.202'
union all select '192.168.121.3'
union all select '192.169.121.50'

select DIstinct parsename(IPAddress,4) +'.'+parsename(IPAddress,3)  from #t

Answer 3

我会使用以下解决方案：

SELECT  x.ID,  y.XmlCol.value('concat(i[1], ".", i[2])', 'VARCHAR(50)')
FROM (
    SELECT  ID, CONVERT(XML, '<root><ip><i>' + REPLACE(REPLACE(IP, ',', '</i></ip><ip><i>'), '.', '</i><i>') + '</i></ip></root>')  AS IPAsXML
    FROM    @SourceTable s
) x OUTER APPLY x.IPAsXML.nodes('root/ip') y(XmlCol)

结果：

<强> Demo here