Question

所以我有一个来自Python3脚本的代码片段，遗憾地产生一个＆＃34;预期的缩进块＆＃34;错误。通常的答案似乎是缩进错误或混合制表符和空格。我检查了这两个，但我的意图似乎很好，我只使用4个空格缩进，没有标签。任何人都有一个想法是错的吗？

for submission in submissions:
    currentUser = submission.author.name
    if currentUser in uniqueUsers:
        # Do Nothing
    else:
        uniqueUsers.append(currentUser)

for user in uniqueUsers:
    print(user)

Answer 1

只要您不想做任何事情，就可以使用传递关键字

for submission in submissions:
    currentUser = submission.author.name
    if currentUser in uniqueUsers:
        pass
        # Do Nothing
    else:
        uniqueUsers.append(currentUser)

for user in uniqueUsers:
    print(user)

Answer 2

您需要撰写pass

的Do nothing内容

for submission in submissions:
    currentUser = submission.author.name
    if currentUser in uniqueUsers:
        pass
    else:
        uniqueUsers.append(currentUser)

for user in uniqueUsers:
    print(user)

Answer 3

如果# Do Nothing实际上没有做任何事情，那么这应该有效：

for submission in submissions:
    currentUser = submission.author.name
    if not currentUser in uniqueUsers:
        uniqueUsers.append(currentUser)

for user in uniqueUsers:
    print(user)

或者正如其他人提到的那样，您也可以使用关键字pass。

Python 3中的意图错误

3 个答案: