Question

我制作了一段代码，用于获取rpi的CPU温度，如果它超过60 C，则在GPIO端口7上发送信号，如果它不超过60 C则不在端口上发送信号但我收到此错误：

 File "tempgate.py", line 17
    def FanController(CPU_temp) :
      ^
SyntaxError: invalid syntax

文件是：

#Module import and variables
import getinfo
import RPi.GPIO as GPIO
import time
import atexit
import datetime
CPU_temp = getinfo.getCPUtemperature
#Start info
st = datetime.datetime.fromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S')
print("[LOG] [" + st + "] Program has started")
#Setup and definitions
try:
    GPIO.setmode(GPIO.BOARD)
    GPIO.setwarnings(False)

def FanController(CPU_temp) :
    CPU_temp = int(float(CPU_temp))
    print(CPU_temp)
    if(int(CPU_temp) > int(60)) :
        GPIO.setup(7, GPIO.OUT)
        ts = time.time()
        st = datetime.datetime.fromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S')
        print("[LOG] [" + st + "] Fan is now on")
        time.sleep(5)
    else :
        GPIO.setup(7, GPIO.IN)
        ts = time.time()
        st = datetime.datetime.fromtimestamp(ts).strftime('%Y-%m-%d %H:%M:%S')
        print("[LOG] [" + st + "] Fan is now off")
        time.sleep(5)

#main app
while True :
    CPU_temp = getinfo.getCPUtemperature()
    print("[LOG] [" + st + "] Cpu CPU_temp is: " + CPU_temp)
    FanController(CPU_temp)
GPIO.cleanup()
atexit.register(GPIO.cleanup())

Answer 1

您有一个与try...无法匹配的未公开except块。

Python上的Python语法无效

1 个答案: