Question

我正在尝试将Activiti 6 activiti-app.war文件部署到Weblogic 12，并且在尝试访问登录页面时遇到以下异常：

java.lang.IllegalArgumentException: ServletContext must not be null
    at org.springframework.util.Assert.notNull(Assert.java:112)
    at org.springframework.web.context.support.WebApplicationContextUtils.getWebApplicationContext(WebApplicationContextUtils.java:108)
    at org.springframework.web.context.support.WebApplicationContextUtils.getWebApplicationContext(WebApplicationContextUtils.java:98)
    at org.springframework.web.filter.DelegatingFilterProxy.findWebApplicationContext(DelegatingFilterProxy.java:305)
    at org.springframework.web.filter.DelegatingFilterProxy.doFilter(DelegatingFilterProxy.java:250)
    at weblogic.servlet.internal.FilterChainImpl.doFilter(FilterChainImpl.java:79)
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.wrapRun(WebAppServletContext.java:3367)
    at weblogic.servlet.internal.WebAppServletContext$ServletInvocationAction.run(WebAppServletContext.java:3333)
    at weblogic.security.acl.internal.AuthenticatedSubject.doAs(AuthenticatedSubject.java:321)
    at weblogic.security.service.SecurityManager.runAs(SecurityManager.java:120)
    at weblogic.servlet.provider.WlsSubjectHandle.run(WlsSubjectHandle.java:57)
    at weblogic.servlet.internal.WebAppServletContext.doSecuredExecute(WebAppServletContext.java:2220)
    at weblogic.servlet.internal.WebAppServletContext.securedExecute(WebAppServletContext.java:2146)
    at weblogic.servlet.internal.WebAppServletContext.execute(WebAppServletContext.java:2124)
    at weblogic.servlet.internal.ServletRequestImpl.run(ServletRequestImpl.java:1564)
    at weblogic.servlet.provider.ContainerSupportProviderImpl$WlsRequestExecutor.run(ContainerSupportProviderImpl.java:254)
    at weblogic.work.ExecuteThread.execute(ExecuteThread.java:295)
    at weblogic.work.ExecuteThread.run(ExecuteThread.java:254)

这是我的weblogic.xml文件：

<?xml version="1.0" encoding="UTF-8"?>
<wls:weblogic-web-app xmlns:wls="http://xmlns.oracle.com/weblogic/weblogic-web-app" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd http://xmlns.oracle.com/weblogic/weblogic-web-app http://xmlns.oracle.com/weblogic/weblogic-web-app/1.5/weblogic-web-app.xsd">
    <wls:weblogic-version>12.1.2</wls:weblogic-version>
    <wls:container-descriptor>
        <wls:prefer-application-packages>
            <wls:package-name>com.google.common.*</wls:package-name>
            <wls:package-name>org.joda.*</wls:package-name>
        </wls:prefer-application-packages>
    </wls:container-descriptor>
</wls:weblogic-web-app>

任何想法如何解决

Answer 1

在WebConfigurer中的DelegatingFilterProxy构造函数中提供webservletcontext对象Servlet Context Listener为我工作。

initSpringSecurity方法中的现有代码片段如下所示

FilterRegistration.Dynamic springSecurityFilter = servletContext.addFilter("springSecurityFilterChain", new DelegatingFilterProxy());

在修改addFilter调用后如下所示：

WebApplicationContext webAppContext = WebApplicationContextUtils.getRequiredWebApplicationContext(servletContext);

FilterRegistration.Dynamic springSecurityFilter = servletContext.addFilter("springSecurityFilterChain", new DelegatingFilterProxy("springSecurityFilterChain",webAppContext));

Answer 2

如果收到错误

未找到WebApplicationContext：没有注册ContextLoaderListener？

在调用方法WebApplicationContextUtils.getRequiredWebApplicationContext时，尝试实例化WebContext，如下所示：

AnnotationConfigWebApplicationContext webAppContext = new AnnotationConfigWebApplicationContext();
        webAppContext.register(ResourceWebConfig.class);

ResourceWebConfig类是：

@Configuration
@EnableWebMvc
public class ResourceWebConfig extends WebMvcConfigurerAdapter {
}

Activiti 6 App + Weblogic 12 =＆＃34; ServletContext不能为空＆＃34;

2 个答案: