Question

对于类型字典

{'key1': ['v1','v2','v3', ...],
 'key2': ['v2','v4', ...],
  ... }

我如何

查找与值v
将k：[值集]对打印到新词典

Answer 1

# answer to 1st question
keys_with_value = [k for k, v in old_dict.iteritems() if "whatever_value" in v]

# answer to 2nd question
new_dict = {}   
for k in keys_with_value:
   new_dict[k] = old_dict[k]

示例：

>>> old_dict = {'key1':['v1','v2','v3'], 'key2':['v2','v4']}
>>> keys_with_value = [k for k, v in old_dict.iteritems() if "v2" in v]
>>> new_dict = {}
>>> for k in keys_with_value:
       new_dict[k] = old_dict[k]

>>> new_dict
{'key2': ['v2', 'v4'], 'key1': ['v1', 'v2', 'v3']}

>>> new_dict = {}
>>> keys_with_other_value = [k for k, v in old_dict.iteritems() if "v1" in v]
>>> for k in keys_with_other_value:
       new_dict[k] = old_dict[k]

>>> new_dict
{'key1': ['v1', 'v2', 'v3']}

Answer 2

实际上，首先回答第二个问题（将任何匹配对找到new_dictionary）更快更简单，然后从中提取密钥列表以回答第一个问题。

old_dict = {'key1': ['v1','v2','v3','v56','v99'],
            'key2': ['v2','v4','v42','v17'],
            'key3': ['v0','v3','v4','v17','v49'],
            'key4': ['v23','v14','v42'],
           }

v = 'v42'
new_dict = dict(pair for pair in old_dict.iteritems() if v in pair[1])
print 'new_dict:', new_dict
# new_dict: {'key2': ['v2', 'v4', 'v42', 'v17'], 'key4': ['v23', 'v14', 'v42']}

keys_with_value = new_dict.keys()
print 'keys_with_value:', keys_with_value
# keys_with_value: ['key2', 'key4']

Answer 3

在python 3中，它甚至更好：

>>> old_dict = {'key1':['v1','v2','v3'], 'key2':['v2','v4']}
>>> keys_with_value = [k for k, v in old_dict.items() if "v2" in v]
>>> new_dict = {k: v for k, v in old_dict.items() if "v2" in v}

与Daniel DiPaolo相同的结果。注意.items（）而不是.iteritems（）。

当与多个值关联的键时，在python中查找值的键

3 个答案: