Question

这是我的代码：

print ("Welcome to International Football Transfers")
inpt = raw_input("Do you want to buy player or sell?")

def lst_of_players():
    if inpt == "buy":
        print ("Here is list of players and their prices")
    players = {
    'Paul Pogba' : '$89,3m',
    'Gareth Bale' : '$85,3m',
    'Cristiano Ronaldo' : '$80m',
    'Gonzalo Higuain' : '$75,3m',
    'James Rodriguez' : '$79,8m',
    'Zlatan Ibrahimovic' : '$56m',
    'Kaka' : '$50m'
    }
    for keys, values in players.items():      #Printing keys and values from dictionary
        return (keys, values)
    print (keys,values)

plyrs = lst_of_players()
print (plyrs)

问题是当我在"buy"中输入raw_input时，我得到的输出是：

Welcome to International Football Transfers
Do you want to buy player or sell?buy
Here is list of players and their prices
('Kaka', '$50m')

***Repl Closed***

我的问题是为什么我只为Kaka而不是所有其他玩家获得输出？

Answer 1

将输入传递给文件并打印结果而不是返回结果。

 def lst_of_players(inpt):       
    if inpt == "buy":      
        print ("Here is list of players and their prices")
        players = {
       'Paul Pogba' : '$89,3m',
       'Gareth Bale' : '$85,3m',
       'Cristiano Ronaldo' : '$80m',
       'Gonzalo Higuain' : '$75,3m',
       'Zlatan Ibrahimovic' : '$56m',
       'Kaka' : '$50m'
        }
       for keys, values in players.items():  

          print (keys,values)



print ("Welcome to International Football Transfers")
inpt = raw_input("Do you want to buy player or sell?")
lst_of_players(inpt)

Answer 2

当在return函数内部评估lst_of_players语句时，该函数返回指定的内容，并退出该函数 - 因此您的print (keys,values)未被执行。< / p>

据我所知，你想要实现的目标可以实现为：

print ("Welcome to International Football Transfers")
inpt = raw_input("Do you want to buy player or sell?")

def lst_of_players():
    if inpt == "buy":
        print ("Here is list of players and their prices")
    players = {
    'Paul Pogba' : '$89,3m',
    'Gareth Bale' : '$85,3m',
    'Cristiano Ronaldo' : '$80m',
    'Gonzalo Higuain' : '$75,3m',
    'James Rodriguez' : '$79,8m',
    'Zlatan Ibrahimovic' : '$56m',
    'Kaka' : '$50m'
    }
    for key, value in players.items():
        print("{}: {}".format(key, value))

lst_of_players()

Answer 3

你在剧本中犯了一些错误：

你从不使用inpt作为你职能的参数，所以你需要将其添加到您的功能中。
返回值时，函数终止，您需要在print循环中调用for。
最后，你只需要打电话给你的功能，没有必要将您的函数分配给变量，然后像上次一样打印它代码行。

尝试这样的想法：

def lst_of_players(inpt):
    if inpt == "buy":
        print ("Here is list of players and their prices")
    players = {
    'Paul Pogba' : '$89,3m',
    'Gareth Bale' : '$85,3m',
    'Cristiano Ronaldo' : '$80m',
    'Gonzalo Higuain' : '$75,3m',
    'James Rodriguez' : '$79,8m',
    'Zlatan Ibrahimovic' : '$56m',
    'Kaka' : '$50m'
    }
    for key, value in players.items():
        print(key, value)

lst_of_players(inpt)

Answer 4

for keys, values in players.items():      #Printing keys and values from dictionary
        return (keys, values) #Does this ONCE

使用return后，函数终止。它将返回第一组键和它循环的值。因此，您只能获得一名玩家的输出。正如第二个答案所说，你可以打印它们而不是返回它们。您还可以将它们附加到列表并返回列表。此外，您需要将inpt作为参数传递给您的函数。

Answer 5

尝试使用列表，而不是字典。例如：

players = ['Paul Pogba : $89,3m',
    'Gareth Bale : $85,3m',
    'Cristiano Ronaldo : $80m',
    'Gonzalo Higuain : $75,3m',
    'James Rodriguez : $79,8m',
    'Zlatan Ibrahimovic : $56m',
    'Kaka : $50m']

为什么不返回所有字典项？

5 个答案: