Question

此查询有什么问题？我的插入需要从其他表中获取数据，但是当我使用select时，它会给我错误。

以下是查询：

INSERT INTO PAYMENT (
  OWNER_HI,
  ACCOUNT_ID,
  DATE_PAYMENT,
  ACCOUNT_VALUE_BEFORE,
  CURRENCY,EXCHANGE_RATE,
  SUM,
  SUM_USD,
  DATE_INPUT,
  OPERATOR_ID,
  DOCUMENT,
  INVOICE_ID)
VALUES (
  OWNER,
  ID,
  TODAY,
  SALDO,
  CURRENCY,
  RATE,
  50,
  (50 * RATE),
  TODAY,
  386,
  'teste sis',
  null)
(SELECT TO_CHAR(SYSDATE, 'YYYY-MM-DD') "NOW" FROM DUAL) TODAY
(SELECT VALUE FROM ACCOUNT WHERE ACCOUNT_ID = 386) SALDO
(SELECT CURRENCY_IDCURRENCY_ID FROM CURRENCY_EXCHANGE WHERE rownum=1 ORDER BY CURRENCY_ID DESC) CURRENCY
(SELECT EXCHANGE_RATE FROM CURRENCY_EXCHANGE WHERE rownum=1 ORDER BY CURRENCY_ID DESC) RATE;

这是错误的：

Erro de SQL：ORA-00933：SQL命令未正确结束
00933. 00000 - ＆＃34; SQL命令未正确结束＆＃34;

Answer 1

也许你的意思更像是

Could not find suitable configuration file.

祝你好运。

Answer 2

我们不能混用INSERT ... VALUES和INSERT ... SELECT语法。选择其中一个。当您需要来自其他表的值时，您需要INSERT ... SELECT。

您要查询的表之间没有任何关系，因此请使用CROSS JOIN。只要您从每个行中只选择一行，这就不会产生问题。

SELECT EXCHANGE_RATE FROM CURRENCY_EXCHANGE WHERE rownum=1 ORDER BY CURRENCY_ID DESC没有按照您的想法执行，因为ROWNUM在排序之前未分配。要获得最顶级的货币，请在子查询中使用ROW_NUMBER()之类的分析函数并对其进行过滤。

我必须做一些猜测，因为你不清楚你正在实施的所有业务规则，但你需要这样的事情：

INSERT INTO PAYMENT ( OWNER_HI, ACCOUNT_ID, DATE_PAYMENT, ACCOUNT_VALUE_BEFORE, CURRENCY,EXCHANGE_RATE, SUM, SUM_USD, DATE_INPUT, OPERATOR_ID, DOCUMENT, INVOICE_ID) select user, -- where does OWNER come from?? saldo.account_id, trunc(sysdate), SALDO.value, CURRENCY.CURRENCY_ID , CURRENCY.EXCHANGE_RATE , 50, (50 * CURRENCY.EXCHANGE_RATE ), trunc(sysdate), 386, 'teste sis', null from ( select CURRENCY_ID, EXCHANGE_RATE, row_number() over (order by CURRENCY_ID DESC ) as rn FROM CURRENCY_EXCHANGE ) currency cross join (SELECT * FROM ACCOUNT WHERE ACCOUNT_ID = 386) SALDO where currency.rn = 1

注意：我忽略了将sysdate转换为字符串（作为“TODAY”），因为将日期存储为字符串是非常糟糕的做法。我希望你只是等待从sysdate剥离时间元素，我们也可以通过截断来实现。

从多个表中进行选择时的Oracle INSERT

2 个答案: