Question

我有一个SQL查询来从joomla网站内的幼儿园表格中获取信息，并做一些数学计算，以了解孩子父母应该每周支付多少钱，然后总结它以了解税收收据的数量。

当我只使用一个孩子时，我得到了正确的金额，但是只要我添加第二个，这些数字就不会与两个孩子相加。

以下是请求：

SELECT
    SUM(t1.test1) AS t1,
    SUM(t2.test2) AS t2
FROM
(
    SELECT
        (COUNT(josnh_facileforms_records.id) * sal1.salaire1) AS test1,
        josnh_facileforms_subrecords.record
    FROM josnh_facileforms_records,
         josnh_facileforms_subrecords
    LEFT JOIN
    (
        SELECT
            LEFT(josnh_facileforms_subrecords.value, 5) AS salaire1,
            josnh_facileforms_subrecords.record AS records1
        FROM josnh_facileforms_records,
             josnh_facileforms_subrecords
        WHERE josnh_facileforms_records.user_id = [id]
              AND josnh_facileforms_records.form = 24
              AND josnh_facileforms_records.id = josnh_facileforms_subrecords.record
              AND josnh_facileforms_subrecords.name LIKE 'enfant1'
        GROUP BY
            josnh_facileforms_subrecords.record
    ) AS sal1 ON sal1.records1 = josnh_facileforms_subrecords.record
    WHERE josnh_facileforms_records.user_id = [id]
          AND josnh_facileforms_records.form = 24
          AND josnh_facileforms_records.id = josnh_facileforms_subrecords.record
          AND josnh_facileforms_subrecords.name LIKE '%di1'
          AND josnh_facileforms_subrecords.value = 'RG'
    GROUP BY
        josnh_facileforms_subrecords.record
) AS t1,
(
    SELECT
        (COUNT(josnh_facileforms_records.id) * sal2.salaire2) AS test2,
        josnh_facileforms_subrecords.record
    FROM josnh_facileforms_records,
         josnh_facileforms_subrecords
    LEFT JOIN
    (
        SELECT
            LEFT(josnh_facileforms_subrecords.value, 5) AS salaire2,
            josnh_facileforms_subrecords.record AS records2
        FROM josnh_facileforms_records,
             josnh_facileforms_subrecords
        WHERE josnh_facileforms_records.user_id = [id]
              AND josnh_facileforms_records.form = 24
              AND josnh_facileforms_records.id = josnh_facileforms_subrecords.record
              AND josnh_facileforms_subrecords.name LIKE 'enfant2'
        GROUP BY
            josnh_facileforms_subrecords.record
    ) AS sal2 ON sal2.records2 = josnh_facileforms_subrecords.record
    WHERE josnh_facileforms_records.user_id = [id]
          AND josnh_facileforms_records.form = 24
          AND josnh_facileforms_records.id = josnh_facileforms_subrecords.record
          AND josnh_facileforms_subrecords.name LIKE '%di2'
          AND josnh_facileforms_subrecords.value = 'RG'
    GROUP BY
        josnh_facileforms_subrecords.record
) AS t2;

我可以再看看这个吗？

Answer 1

好吧，这是一个新手问题我是如此专注于子查询，我忘了将FROM标签中的子查询与左标签链接。

具有多级子查询的SQL查询

1 个答案: