Question

如何从函数外部调用具有相同依赖性的函数？它似乎不是全局的，因此被调用的函数不了解FeatureLayer

require(
[
"esri/map",
"esri/layers/FeatureLayer",
"esri/dijit/PopupTemplate",
"esri/geometry/Point",
"esri/graphic",
"dojo/domReady!"
], 
function(Map, FeatureLayer, PopupTemplate, Point, Graphic){
   map = new Map("mapDiv", { basemap: "streets", center: [22, 65], zoom: 5 });
   getBasestationList();
};
});

function getBasestationList() {
    fromdatetime = fromdatetime.toLocaleString();
    todatetime = todatetime.toLocaleString();
    $.ajax(
    {
        type: "post", 
        url: "{% url 'get_latest_basestation_list' %}",
        data: 
        {
            "csrfmiddlewaretoken": "{{ csrf_token }}",
            "fromdate": fromdatetime,
            "todate": todatetime,
        },
        success: function (data, status) 
        { 
            featureLayer = new FeatureLayer(data, { id: 'basestations' });
            map.addLayers([featureLayer]);
        },
        error: function (request, status, error) 
        {
            alert(request.responseText);
        }
     }); 
 };

然而，这给了我一个错误，即没有定义FeatureLayer，因为它没有那个依赖。如何向外部函数添加依赖项并从我的函数中调用它？

Answer 1

您可以将FeatureLayer对象传递给getBasestationList（FeatureLayer）等方法，然后查看是否可以引用它？

另一种方法是声明一个全局变量并为其指定FeatureLayer引用。

您的代码问题是函数getBasestationList（）似乎在范围之外。因此，您需要定义一个全局变量来使用该对象。

Answer 2

将函数getBasestationList（）放在require函数中，如代码示例

require(
[
"esri/map", "esri/layers/FeatureLayer", "esri/dijit/PopupTemplate",
"esri/geometry/Point", "esri/graphic", "dojo/domReady!"
], 
function(Map, FeatureLayer, PopupTemplate, Point, Graphic){
  function getBasestationList() {
    fromdatetime = fromdatetime.toLocaleString();
    todatetime = todatetime.toLocaleString();
    $.ajax(
    {
        type: "post", 
        url: "{% url 'get_latest_basestation_list' %}"
    }); 
  };
  map = new Map("mapDiv", { basemap: "streets", center: [22, 65], zoom: 5 });
  getBasestationList();
});

requirejs以相同的依赖性调用外部函数

2 个答案: