Question

功能定义＆amp;变量：

def secret_formula(started):
    jelly_beans = started * 500
    jars = jelly_beans / 1000
    crates = jars / 100
    return jelly_beans, jars, crates

start_point = 10000 / 10

print statement：

print """crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % (start_point, (secret_formula(start_point)))

我得到的错误信息是“％d格式：需要一个数字，而不是一个元组。请帮我修理一下。我是编程新手......还是不可能将变量和被调用的函数打包到同一个formattet打印中？

Answer 1

python 2中的变体：

print """crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % ((start_point, ) + secret_formula(start_point))

我通过将元组(start_point, )添加到函数的结果来创建一个新元组。

在python 3中，你可以unpack the tuple with a *：

print("""crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % (start_point, *secret_formula(start_point)))

Answer 2

考虑添加*以解包元组（python 3.x解决方案）：

print ("""crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % (start_point, *(secret_formula(start_point))))

如果你正在使用python 2.x可以输入：

start_point = 10000 / 10
res = secret_formula(start_point)
print """crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % (start_point, res[0], res[1], res[2])

Answer 3

#According to zen of python Explicit is better than implicit, so

bs, js, cs = secret_formula(start_point)

print """crazy different style:
startpoint: %d\n
beans:\t\t %d\n
jars:\t\t %d\n
crates:\t\t %d\n
""" % (start_point, bs, js, cs)

Answer 4

使用python 3

def secret_formula(started):
    jelly_beans = started * 500
    jars = jelly_beans / 1000
    crates = jars / 100
    return jelly_beans, jars, crates

start_point = 10000 / 10

print ("startpoint : {0} \n \
       beans:\t\t {1}  \n \
       jar :\t\t {2}".format(start_point,*secret_formula(start_point)[:2]))

输出

startpoint : 1000.0 
    beans:       500000.0  
    jar :        500.0

打印格式字符串函数和变量（python）

4 个答案: