使用Swift 3错误'缺少必需参数:grant_type'

时间:2017-07-11 11:44:34

标签: ios twitter swift3

我正在使用Twitter API,我想获得access_Token但是我收到了这个错误:

{
"errors" : [
  {
    "message" : "Missing required parameter: grant_type",
    "label" : "forbidden_missing_parameter",
    "code" : 170
  }
 ]
}. 

我的要求如下:

let dict = ["grant_type" : "client_credentials"]  

requestPOSTURL("https://api.twitter.com/oauth2/token", params: dict as [String : AnyObject] , headers: ["Authorization" : "Basic " + strHeader, "Content-Type" : "application/x-www-form-urlencoded;charset=UTF-8"], success: { (json) in

        Helper.sharedInstance.Print(json as AnyObject)

    }, failure: {(error) in

        Helper.sharedInstance.Print(error as AnyObject)
    }). 

func requestPOSTURL(_ strURL : String, params : [String : AnyObject]?, headers : [String : String]?, success:@escaping (JSON) -> Void, failure:@escaping (Error) -> Void){
    sessionManager.request(strURL, method: .post, parameters: params, encoding: JSONEncoding.default, headers: headers).responseJSON { (responseObject) -> Void in
        //print(responseObject)
        if responseObject.result.isSuccess {
            let resJson = JSON(responseObject.result.value!)
            success(resJson)
        }
        if responseObject.result.isFailure {
            let error : Error = responseObject.result.error!
            failure(error)
        }
    }
}

我试图获取access_Token(OAuth)但无法获取因为上述错误即将发生。

1 个答案:

答案 0 :(得分:0)

我也遇到过类似的问题,并且使用本机NSMutableURLRequest进行了修复。 https://stackoverflow.com/a/59472862/1528061