如何解析Json对Swift对象的响应

Question

您好我是swift语言的初学者，在我的项目中，我使用的是Web服务，在得到响应之后如何解析以下对Swift对象的响应可以帮助我一些

响应： -

[
    {
        "id" : 1,
        "first_name": "John",
        "last_name": "Smith",
        "age": 25,
        "address": {
            "id": 1,
            "street_address": "2nd Street",
            "city": "Bakersfield",
            "state": "CA",
            "postal_code": 93309
         }

    }
]

ModelClass： -

class Address:NSObject{

struct Address {
    let objID: Int?
    let streetAddress: String?
    let city: String?
    let state: String?
    let postalCode: String?
}

struct User {
    let objID: Int?
    let firstName: String?
    let lastName: String?
    let age: Int?
    let address : Address?
   }
}

的ViewController： -

func finalResponse(response : AnyObject){

    let addressArray = response as! NSArray;
        for items in addressArray{
        }
  }

Answer 1

在swift 4中，它变得更容易

您的模型类看起来像这样 键应与json响应相同或使用enum更改名称

struct Address: Decodable {
    let objID: Int?
    let streetAddress: String?
    let city: String?
    let state: String?
    let postalCode: String?
}

struct User: Decodable {
    let objID: Int?
    let firstName: String?
    let lastName: String?
    let age: Int?
    let address : Address?
   }
}

您的视图Controller类看起来像这样

try decoder.decode([User.self], from: jsonData)

Answer 2

这是objective-c swift 1,2,3

中的旧日方法

这是模型类

class SafeJson: NSObject{

    override func setValue(_ value: Any?, forKey key: String) {
        let firstCharacter = String(key.characters.first!).uppercased()
        let range = NSMakeRange(0,1)
        let valuex = NSString(string: key).replacingCharacters(in: range, with: firstCharacter)
   //     let valuex = key.replacingCharacters(in: range, offsetBy: 0), with: firstCharacter)
        let selector = NSSelectorFromString("set\(valuex):")
        let respond = self.responds(to: selector)
        if !respond{
            return
        }
        super.setValue(value, forKey: key)
    }
}


class Model:SafeJson{

       // var thumbnail_image_name: String?
        var title: String?
        var number_of_views: NSNumber?
        var channel: Channel?
        override func setValue(_ value: Any?, forKey key: String) {
            if key == "channel"{
                self.channel = Channel()
                let dictionary = value as! [String: AnyObject]
                self.channel?.setValuesForKeys(dictionary)

            }else{
            super.setValue(value, forKey: key)
            }
        } 
        init(dictionary: [String: AnyObject]) {
            super.init()
            setValuesForKeys(dictionary)
        }
    }

    class Channel:SafeJson{
        var name: String?
        var profile_image_name: String?

    }

在您的View控制器类中您必须将响应传递给Model.init 它会自动保存到模型

但是在swift 4中，setValueForKey被删除 你必须使用可解码

Answer 3

警告，没有测试它，所以让我知道任何警告，并将调整

对于Swift3

func finalResponse(response : AnyObject){

    var result: [Address] = []
    let json = response as! [String:AnyObject]
            // ITERATE THROUGH THE ARRAY OF DICTIONARIES
        for item in json {
          // a WILL BE THE MAIN OBJECT YOU'RE CREATING
            var a = Adress()
            a.objID = item["id"] as! Int
                 .....
                 // REPEAT FOR EVERY ELEMENT UNTIL YOU REACH NEXT SUBCLASS
                 .....
            // CREATE A NEW DICTIONARY FOR THE SUBCLASS Address
            var b = item["address"] as! Dictionary<String, String>
            a.address.objID = b["id"] as! Int

            // IF YOU DON'T WANT TO CREATE var b YOU CAN WRITE
            // a.address.objID = a["address"]["id"]     INSTEAD

            // ADD YOUR OBJECT TO RESULT
            result.append(a)
        }
  }

Answer 4

Herr是解析JSON数据中数据的代码。在我在代码中注释的位置创建结构。

do{
    let json = try JSONSerialization.jsonObject(with: yourJSONData!, options: []) as? [Any]

    let firstUser = json?[0] as? [String: Any]
    let id = firstUser?["id"] as? Int
    let firstName = firstUser?["first_name"] as? String
    //etc... for other keys
    let address = firstUser?["address"] as? [String, Any]
    let streetAddress = address?["street_address"] as? String
    let state = address?["state"] as? String
    //etc... create your address struct here and then create the user struct
    dump(firstPerson?["lastName"])
}catch let error{

}